What are the period and phase shift in the function y=4sin(3X+Pie/4)-2?

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In the function y=4sin(3X+π/4)-2, the period is determined by the coefficient of X, which is 3, leading to a period of 2π/3. The phase shift is calculated from the term π/4, resulting in a shift of -π/12. While the standard form A*sin(kx+φ) provides a quick way to find these values, understanding how to derive them from the function itself is also important. The periodicity of the function can be confirmed by the condition f(x+T)=f(x), where T represents the period. This discussion emphasizes the importance of both standard form and functional analysis in determining period and phase shift.
Ry122
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In the function
y=4sin(3X+Pie/4)-2
what determines the period and phase shift?
I know that 4=Amplitude
The answer in the back of the textbook says
Period=2pie/3
Phase Shift=-pie/12
 
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standard form:
A\sin (kx+\phi)
period is given by 2\pi/k
 
mjsd said:
standard form:
A\sin (kx+\phi)
period is given by 2\pi/k

Yeah but i think it is better to do it this way, because not always you can immediately determine the period of a function based on that standard form. I think it is better to first know how to come up to that standard form.

so how do we know whether a function is periodic or not?

f(x+T)=f(x), where T is the period.
so after you substitute these values you will be able to find the period of that function, which is the same as ry122 said on his op.
 
dessert =/= a mathematical constant, Ry
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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