What Are the Pressure and Speed of Water in a Fire Hose Tip?

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The discussion focuses on calculating the pressure and speed of water in a fire hose tip based on given parameters. The initial gauge pressure in the hose is 3.0 x 10^5 Nm-2, with a flow speed of 4.0 m/s. Using the continuity equation and Bernoulli's principle, the volumetric flow rate is determined to be 0.00916 m3/s, leading to a calculated speed at the hose tip of 18.67 m/s. The pressure at the tip is computed to be approximately 133,716 N/m^2 after correcting for arithmetic errors. The accuracy of these calculations is questioned in relation to tutorial answers.
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Homework Statement



The gauge pressure in a horizontal fire hose of diameter 5.4 cm is 3.0 x 105 Nm-2 and the speed of flow is 4.0 ms-1. The fire hose ends in a metal tip of diameter 2.5 cm. What are the pressure and the speed of the water in the tip?

Homework Equations




P+ρgh+0.5ρv^2=Constant
Volumetric Flow rate = A*v
Mass Flow Rate = ρ*Volumetric Flow rate

The Attempt at a Solution



Volumetric Flow rate = 0.00229*4 = 0.00916m3/s
Speed at end of hose = 0.00916/0.000491 = 18.67m/s

300000 + (0.5*1000*4^2) = P2 + (0.5*1000*18.67)
= 308000 = P2+174845

∴ P2 = 308000-17845 = 133155Pascals or 1.3 Bar

I am just checking this is right. As this is the answer I keep getting but the tutorial answers show something different.
 
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You have to square the 18.67. Check your arithmetic. I get 133,716 N/m^2.

AM
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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