- #36
Terra Incognita
- 37
- 0
vanesch said:B
I didn't look yet at that paper ; however I've been playing myself also with H_q x H_p stuff for fun (not thinking any serious scientist would do something like that :-). What I found was that the dynamics is trivial: each |p0,q0> state is an eigenstate of the hamiltonian and hence nothing ever happens. P and Q commute with each other, and with the hamiltonian, so in the Heisenberg picture, because [P,H] = [Q,H] = 0, dP/dt = 0 = dQ/dt. Because all variables are supposed to be functions of P and Q, all variables are constants of motion. Nothing moves.
I even think it stays at [q0,p0,t]...
Oh dark side of the force, what are you saying to the little padawan!
Master, I think you have to review the problem .
In the Koopman-von Neumann approach, we have rho(q,p,t)= <psi||q,p><q,p|psi>= |psi(q,p,t)|^2. There is a lot of papers studying this formulation, you just have to search through arxiv (very instructive).
rho is the probability density that obeys the plain old classical Liouville equation.
if you have the initial state [q0,p0,to] with certainty=> rho(q,p,to)= delta(q-qo)deltal(p-po)
And at time t: rho(q,p,to)= delta(q-q(t))delta(p-p(t)) where q(t) and p(t) is the path of the particle (plain old Newton equation). => the particle moves on the phase space.
TI.