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Homework Statement
1) ok , first we have a solution of :
MnO2, C6H5COO- , OH-
we add Hydrochloric acid, the following reactions happen :
OH- + H3O+ = H2O
C6H5COO- + H3O+ = C6H5COOH + H2O
ok , now we are told that if we put in more Hydrochloric acid than needed, CO2 gas escapes, a question asks me for the equations of the reactions that produce this CO2
I am just told these Acid/Base couples :
HCO3- / CO3-2
CO2, H2O / HCO3-
2) No, with the same solution, with Hydrochloric acid being introduced in about the right proportions, we add a solution of (2Na+ +SO3-2)
Here, another question asks me for the equation of the reaction between MnO2 and SO2,H20
Here i am just told these Red/Ox couples :
MnO2 / Mn+2
SO3-2 / SO2, H2O
The Reaction environment is acid
Homework Equations
The Attempt at a Solution
1)the semi equations :
HCO3- = CO3-2 + H+
CO2 + H2O = HCO3- + H+C6H5COOH + H3O(+) = C6H5 + CO3-2 + 3H+ + H (cannot be H alone so * 2) :
2C6H5COOH + 2H3O(+) = 2C6H5 + 2CO3-2 + 6H+ + H2
then
CO3-2 + H+ = HCO3-
then
HCO3- + H+ = H2O + CO2
(here, I am really not sure of my equations,and the paper doesn't even tell me that H2 gas escapes)2) The semi equations :
MnO2 + 4H+ 2e- = Mn+2 + 2H2O
SO3-2 + 2H+ = SO2 + H2O (no e- in the reactions !, how can it be an Ox/red reaction then ?)
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