What Are the Restricted x Values for the Integral of dx/(sqrt(d^2 + x^2))?

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The integral of dx/(sqrt(x^2 + y^2)) can yield two valid results differing by a constant, specifically ln((x + sqrt(x^2 + y^2))/d) and ln(x + sqrt(x^2 + y^2)). The constant 'd' represents a specific distance related to the problem context. The results are valid for any x and y where x^2 + y^2 is not equal to zero. Understanding the role of 'd' clarifies the integration process and its implications for restricted x values.
carlosbgois
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Hi there. Evaluating the expression \int\frac{dx}{\sqrt{x^{2}+y^{2}}} I can get to the result ln(\frac{x+\sqrt{x^{2}+y^{2}}}{d}), but in my book it goes from this directly to ln (x+\sqrt{x^{2}+y^{2}}), a result wolframalpha says is valid for 'restricted x values'. What does it mean? What are those restricted values? Why?

Many thanks.
 
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carlosbgois said:
Hi there. Evaluating the expression \int\frac{dx}{\sqrt{x^{2}+y^{2}}} I can get to the result ln(\frac{x+\sqrt{x^{2}+y^{2}}}{d}), but in my book it goes from this directly to ln (x+\sqrt{x^{2}+y^{2}}), a result wolframalpha says is valid for 'restricted x values'. What does it mean? What are those restricted values? Why?

Many thanks.



Well, since this is indefinite integration both the results are correct as their difference is just the constant -\ln d.

The question is: where did you get the constant d from??

The result is valid for any values of x,y, s.t. x^2+y^2\neq 0

DonAntonio
 
Thank you. 'd' is actually a constant length (the distance from a point p to a disk, in an axis that goes through the center of the disk)
 

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