- #1
matpo39
- 43
- 0
find all solutions of the given equation: (z+1)^4=1-i
im not sure if i did this right, but here's what i did
the first thing that i did was notice that
1-i = 2^1/2 * (cos (pi/4) + i*sin(pi/4))
then i found
z= [2^(1/2*1/4) * (cos (pi/4) + i*sin (pi/4) )^1/4] -1
then using de moivre's thrm
z= {2^3/4 *(cos [pi/16 +2k*pi/16] + i*sin[pi/16 + 2k*pi/16])}-1 ; k=0,1,2,3
does this look right?
thanks
im not sure if i did this right, but here's what i did
the first thing that i did was notice that
1-i = 2^1/2 * (cos (pi/4) + i*sin(pi/4))
then i found
z= [2^(1/2*1/4) * (cos (pi/4) + i*sin (pi/4) )^1/4] -1
then using de moivre's thrm
z= {2^3/4 *(cos [pi/16 +2k*pi/16] + i*sin[pi/16 + 2k*pi/16])}-1 ; k=0,1,2,3
does this look right?
thanks