What Are the Solutions to These Circular Motion Problems?

In summary, the conversation discussed various questions related to centripetal acceleration, linear velocity, angular velocity, and radius in a circular motion. The first question involved drawing a diagram and calculating the distance traveled. The second and third questions involved calculating the centripetal acceleration using the given equations. For the fourth question, the expert suggested considering the block's motion and the tension in the string to determine the suitable angle for the centripetal acceleration.
  • #1
issh
3
0

Homework Statement


IMG.jpg



Homework Equations


Centripetal Acceleration: a=v2/r or a=w2r
where a= Centripetal Acceleration
v= Linear Velocity
r= Radius
w=angular velocity


The Attempt at a Solution


Question Number 1: Drew a diagram of a circular with one point being O, another being P and another being A, Radius of Circle is 3.6m, and joined O and P to a 25o
MIGHT BE WRONG

Question Number 2:
Turn of 90o takes 0.4 seconds
Therefore 90degree/0.4 seconds = 225 degrees per second or
Therefore using equation
a=w2r
a=2252*0.45
a=22781.25degrees/sec

Pretty sure this is also wrong as for acceleration, it seems too fast

Question Number 3:
Drew diagram--> Circle[Radius 12 cm][2 Revolutions per second]
a=w2r


Question Number 4:
Honestly have no idea how to start
 
Physics news on Phys.org
  • #2
For 1, since the speed on and off the circular path remains constant, then the distanced traveled in an equal amount of time is identical. This means OA = OP. What remains is to calculate OP which can be done using simple circle geometry.

For 2 and 3, you look to be on the right track.

For 4, consider the block's motion. Since the car follows a circle of radius 150m at a speed of 8m/s the block must do the same. The string is the thing accelerating the block, so the angle will be such that the tension offers the suitable amount of centripetal acceleration.
 
  • #3
Thanks Yuqing
For question 1, pretty sure its correct!
Due to fact speed of object is identical(from OP to OA), and also same time, therefore DistanceOA = Distance OP

Find circumference of circle then find length of 25degree

Therefore
C(25degree)= 2*pi*3.6*(25/360)
C(25degree)=1.57m

Thanks

now for Q2-4!
 

FAQ: What Are the Solutions to These Circular Motion Problems?

1. What is circular motion?

Circular motion is a type of motion in which an object moves in a circular path around a fixed point or axis. This motion can be uniform, meaning the object moves at a constant speed, or non-uniform, meaning the speed changes along the circular path.

2. What causes circular motion?

Circular motion is caused by the centripetal force, which is the force that pulls an object towards the center of the circular path. This force is necessary to keep the object moving in a circle instead of moving in a straight line.

3. How is circular motion different from linear motion?

The main difference between circular motion and linear motion is the direction of the motion. In linear motion, the object moves in a straight line, while in circular motion, the object moves in a circular path. Additionally, the acceleration in circular motion is constantly changing, while in linear motion, it can be constant or changing.

4. What is the relationship between speed and radius in circular motion?

The speed of an object in circular motion is directly proportional to the radius of the circular path. This means that as the radius increases, the speed of the object also increases. This relationship is expressed by the formula v = (2πr)/t, where v is the speed, r is the radius, and t is the time.

5. What are some real-life examples of circular motion?

Circular motion can be observed in many natural and man-made phenomena. Some examples include the motion of planets around the sun, the motion of a Ferris wheel, the motion of a spinning top, and the motion of a satellite orbiting the Earth.

Back
Top