What are the voltages generated from this current source?

In summary, the voltages generated from a current source depend on the load resistance connected to it, following Ohm's Law (V = I × R). The voltage can vary based on the current supplied by the source and the resistance of the load, resulting in different voltage outputs for different load conditions.
  • #1
zenterix
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Homework Statement
The circuit shown below contains two nonlinear devices and a current source. The characteristics of the two devices are given. Determine the voltage ##v## for
Relevant Equations
(a) ##i_S=1##A, (b) ##i_S=10##A, (c) ##i_S=1\cos{t}##.
Here is the circuit and the v-i characteristics
1702630454250.png


KCL gives us ##i_S=i_1+i_2##.

Thus, (a) and (b) are solved quickly by noting that for ##v\in [0,1]## we have ##i_1+i_2=0## so ##v## can't be in this interval for a positive current.

If we try ##v\in [1,\infty)## then we get ##i_S=1+(-2+v)=v-1##.

Thus, ##i_S=1##A gives ##v=2##V and ##i_S=10##A gives ##v=11##V.

My question is about item (c) where ##i_S=\cos{(t)}##.

What I did was consider four different cases related to the possible value of ##v##. All I did in each case was consider the KCL equation in the context of a restriction on values of ##v##. Note that only cases 2 and 3 are relevant to the solution of (c).

Case 1: ##v\in [1,\infty)##

From the KCL equation, ##i_S=-1+v##, which graphically is

1702630726220.png

and we see that ##v## satisfies our constraint when ##i_S\geq 1##.

Case 2: ##v\in [0,1)##

Here we have simply ##i_S=0##.

Case 3: ##v\in [-1,0)##

Then, ##i_S=v##

Case 4: ##v \in (-\infty, -1)##

Then, ##i_S=-1##

Putting all of this together we have

1702631251429.png


We know that ##i_S## is a sinusoid that varies between -1 and 1. Thus, ##v## takes on values between -1 and 2.

It seems that

$$v(i_S)=\begin{cases} i_S+1,\ \ \ \ \ i_S\in (0,1) \\ i_S,\ \ \ \ \ i_S\in [-1,0] \end{cases}$$

$$v(t)=\begin{cases} \cos{(t)}+1,\ \ \ \ \ t\in (-\pi/2,\pi/2) \\ \cos{(t)},\ \ \ \ \ t\in (\pi/2,3\pi/2) \end{cases}$$

My question is what happens when ##i_S=0##?
 
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  • #2
@berkeman What difference does it make if I write v-i characteristics rather than V-I characteristics that you edited my title?

Agarwal, "Foundations of Analog and Digital Circuits":
1702691623949.png
 
  • #3
zenterix said:
@berkeman What difference does it make if I write v-i characteristics rather than V-I characteristics that you edited my title?
Good question. For stand-alone symbols, it's more common in my experience to use V and I. However if you are writing the time functions explicitly, then ##v(t)## ##i(t)## would probably be more appropriate. Remember that lowercase "i" or "j" is often used for complex exponents.
 
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FAQ: What are the voltages generated from this current source?

What is the relationship between voltage and current in a current source?

In an ideal current source, the current is constant regardless of the voltage across its terminals. However, in practical current sources, the voltage can vary depending on the load resistance and the internal characteristics of the source.

How do you calculate the voltage across a resistor connected to a current source?

The voltage across a resistor connected to a current source can be calculated using Ohm's Law: V = I * R, where V is the voltage, I is the current from the current source, and R is the resistance.

Can a current source generate a high voltage?

Yes, a current source can generate a high voltage if the load resistance is high enough. The voltage is determined by the product of the current and the load resistance, so with a high resistance, the voltage can become quite large.

How does the internal resistance of a practical current source affect the voltage?

The internal resistance of a practical current source can cause a voltage drop within the source itself, which affects the overall voltage available to the external circuit. This internal resistance can limit the maximum voltage that the source can provide.

What happens to the voltage if the load resistance is zero?

If the load resistance is zero (short circuit), the voltage across the load will be zero as well. However, this can cause the current source to deliver an excessive current, potentially leading to damage if the source is not designed to handle such conditions.

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