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1. Six dogs, each having a mass of 32 kg, pull a 325 kg sled horizontally across ice. If each dog applies a force of 86 N [fwd], what average acceleration es the sled experience? Assume that friction is negligible.
Equation:
F=ma
My solution:
6 x 86 N= 516 N
F=ma
a= F/m
a= 516 N [fwd]/ 325 kg
a= 1.588 m/s2
a= 1.6 m/s2
I just have a problem understanding the question. Help please!![Frown :frown: :frown:](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Equation:
F=ma
My solution:
6 x 86 N= 516 N
F=ma
a= F/m
a= 516 N [fwd]/ 325 kg
a= 1.588 m/s2
a= 1.6 m/s2
I just have a problem understanding the question. Help please!