What average power does the boy need to produce?

[chwala]

Homework Statement

see attached Number 3 (highlighted in red)

Relevant Equations

Power and energy

In my approach, i have

$F_{Resolved} = 300 \cos 60^{\circ} = 150$ Newtons.

I also have,

... from $v=u +at$
$2=0 +6a$
$a= \dfrac{1}{3}$.

$F=ma$
$F=30 ×\dfrac{1}{3} = 10$ Newtons

Therefore,

$P= \dfrac{(150+10) ×6}{6} = 160$ W

Insight is welcome. Thanks.

 

[haruspex]

$F_{Resolved} = 300 \cos 60^{\circ} = 150$ Newtons.

What force are you calculating, and where does that angle come from?

I also have,

... from $v=u +at$
$2=0 +6a$
$a= \dfrac{1}{3}$.

We are not told whether the boy starts at rest.

$P= \dfrac{(150+10) ×6}{6} = 160$ N

The Newton is a unit of force, not power.

 

[chwala]

Typo will amend that...

 

[haruspex]

Typo will amend that...

Ok, but my first point in post #2 is the important one.