What Causes Pressure Changes Along a Pipe?

In summary, the conversation discusses the concept of pressure increase along the inner wall of a pipe, as well as the potential effects of a longer outer wall on the flow of liquid. The discussion also touches on the role of centrifugal forces and the creation of eddies in this scenario. Ultimately, the conclusion is that the pressure at the outer wall should be higher than at the inner wall, contradicting the initial assumption.
  • #1
foo9008
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4

Homework Statement


In this notes , i was told that there is an increase in pressure along the inner wall

Homework Equations

The Attempt at a Solution


IMO , it should be there is increase in pressure at the outer wall , as we can see , the outer wall is longer , so the water would flow slower, resulting in the increases in pressure , am i right ?
 

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  • #2
If the outer wall is longer, then the stuff has to move faster there, isn't it ?

Cf river bends: on the outer edge sand is being eroded, on the inner sand is being deposited. That's how you get meandering.
 
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  • #3
BvU said:
If the outer wall is longer, then the stuff has to move faster there, isn't it ?

Cf river bends: on the outer edge sand is being eroded, on the inner sand is being deposited. That's how you get meandering.
i still don't understand , can you explain further?
 
  • #4
foo9008 said:
the outer wall is longer , so the water would flow slower
It's this assumption you want to reconsider.
I don't know if the context is for laminar flow or for turbulent flow. The latter is easiest to imagine: radial pressure profile flat in the straight sections. To make the longer path for the outer turn the liquid has to flow faster. And on the inside the shorter path necessitates a slower flow. So there is a pressure profile (Bernoulli) in the 45 degree plane (lower right to top left in your picture) : higher pressure on the inside to lower pressure at the outer point. The guide vanes can prevent the liquid from responding to that pressure difference with an outward flow (so in an undesired drection) by 'pushing' it in the right direction (f = dp/dt).
 
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  • #5
BvU said:
It's this assumption you want to reconsider.
I don't know if the context is for laminar flow or for turbulent flow. The latter is easiest to imagine: radial pressure profile flat in the straight sections. To make the longer path for the outer turn the liquid has to flow faster. And on the inside the shorter path necessitates a slower flow. So there is a pressure profile (Bernoulli) in the 45 degree plane (lower right to top left in your picture) : higher pressure on the inside to lower pressure at the outer point. The guide vanes can prevent the liquid from responding to that pressure difference with an outward flow (so in an undesired drection) by 'pushing' it in the right direction (f = dp/dt).
do you mean if the flow is turbulent , the water at the outer region of pipe(longer) is flowing faster , why is it so ?
 
  • #6
On the lower left of the picture, planes of equal pressure are horizontal. On the right vertical. They have to change orientation but are reluctant to do so (inertia).

upload_2016-4-21_10-43-4.png


On the inside, the liquid has to 'brake': it wants to flow faster but is held up. So pressure is rising.
On the outside the pressure drops to accelerate the liquid.
Velocity profile follows (Bernoulli)

I've only drawn a few blue arrows to suggest this.
In the horizontal direction something similar happens
 
  • #7
BvU said:
On the lower left of the picture, planes of equal pressure are horizontal. On the right vertical. They have to change orientation but are reluctant to do so (inertia).

View attachment 99457

On the inside, the liquid has to 'brake': it wants to flow faster but is held up. So pressure is rising.
On the outside the pressure drops to accelerate the liquid.
Velocity profile follows (Bernoulli)

I've only drawn a few blue arrows to suggest this.
In the horizontal direction something similar happens
whaty do you mean by On the inside, the liquid has to 'brake': it wants to flow faster but is held up.? how can the liquid be held up ?
 
  • #8
Hehe, you ask good questions. I'll have to look up a few things that I seem to have imagined wrongly... (what I wrote is contradicted by figure 2..., but I do like figure 3, at least if my interpretation is right...)
 
  • #9
BvU said:
Hehe, you ask good questions. I'll have to look up a few things that I seem to have imagined wrongly... (what I wrote is contradicted by figure 2..., but I do like figure 3, at least if my interpretation is right...)
ok , let me know if you have found out the new explanation .
 
  • #10
BvU said:
Hehe, you ask good questions. I'll have to look up a few things that I seem to have imagined wrongly... (what I wrote is contradicted by figure 2..., but I do like figure 3, at least if my interpretation is right...)
hi , do you have any idea about the question that i asked earlier?
 
  • #11
I didn't reply to this thread originally because it made no sense to me either. I was hoping someone more expert might explain it. Anyway, here's my inexpert 2c.
One problem with the "has to go faster" argument is that there is no obvious reason why it has to keep up.
The referenced text mentions centrifugal forces. The argument from that, surely, is that a net radially inward force must exist, which implies higher pressure on the outside. Since that implies the outside flow would slow down into the bend (relative to the inside flow, at least) it suggests the creation of a counterclockwise eddy.
 
  • #12
haruspex said:
I didn't reply to this thread originally because it made no sense to me either. I was hoping someone more expert might explain it. Anyway, here's my inexpert 2c.
One problem with the "has to go faster" argument is that there is no obvious reason why it has to keep up.
The referenced text mentions centrifugal forces. The argument from that, surely, is that a net radially inward force must exist, which implies higher pressure on the outside. Since that implies the outside flow would slow down into the bend (relative to the inside flow, at least) it suggests the creation of a counterclockwise eddy.
so , the notes is wrong ? the pressure at the outer wall should higher than the inner wall ?
 
  • #13
foo9008 said:
so , the notes is wrong ? the pressure at the outer wall should higher than the inner wall ?
That's how I see it, but, as I wrote, I do not consider myself expert in hydrodynamics.
 
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  • #14
I looked at the link in post #8 with interest, and also at ref.1 therein (*).
BvU said:
Hehe, you ask good questions. I'll have to look up a few things that I seem to have imagined wrongly... (what I wrote is contradicted by figure 2..., but I do like figure 3, at least if my interpretation is right...)
Clearly, even my interpretation of fig. 3 was wrong ands the pressure at outer wall is higher -- and consequently (?) the velocity is lower. So the first paragraph of your notes is disproved and my defence was ill-advised.

I still think
foo9008 said:
the outer wall is longer , so the water would flow slower
that this is not a cause-effect relation, but that's only as a physicist (and obviously I'm not a fluid flow expert :frown:).

Some aspects of this elbow flow are counter-intuitive, others make sense. Thank you for bringing it up in this critical manner !

(*)
I particularly like the (page 14)
It is this horizontal gradient that is ultimately responsible for keeping the flow turned along the axis of the pipe
and it would be interesting to check (by calculation or from experiment) the claim in your notes that the insertion of guide vanes eases the situation and reduces the pressure drop. My bet is that it does.
 
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  • #15
BvU said:
I particularly like the (page 14)
It is this horizontal gradient that is ultimately responsible for keeping the flow turned along the axis of the pipe​
This strikes me as essentially the same as the mention of centripetal acceleration in the text cited in the OP. It may be that the claim there that the pressure is therefore greatest on the inside of the bend is simply a typo.
BvU said:
) the claim in your notes that the insertion of guide vanes eases the situation and reduces the pressure drop.
Again, that is consistent with the centripetal acceleration view. The vanes can supply the centripetal force locally, instead of the entire force having to be transmitted from the outside of the elbow.

I found the velocity map on page 13 particularly interesting. It shows that the flows follow two counter-rotating helices around the curve.
 
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  • #16
BvU said:
I looked at the link in post #8 with interest, and also at ref.1 therein (*).
Clearly, even my interpretation of fig. 3 was wrong ands the pressure at outer wall is higher -- and consequently (?) the velocity is lower. So the first paragraph of your notes is disproved and my defence was ill-advised.

I still think that this is not a cause-effect relation, but that's only as a physicist (and obviously I'm not a fluid flow expert :frown:).

Some aspects of this elbow flow are counter-intuitive, others make sense. Thank you for bringing it up in this critical manner !

(*)
I particularly like the (page 14) and it would be interesting to check (by calculation or from experiment) the claim in your notes that the insertion of guide vanes eases the situation and reduces the pressure drop. My bet is that it does.
Ok, since this is not an cause and effect relationship , why the pressure at the outer wall of pipe is higher?
 
  • #17
haruspex said:
This strikes me as essentially the same as the mention of centripetal acceleration in the text cited in the OP. It may be that the claim there that the pressure is therefore greatest on the inside of the bend is simply a typo.

Again, that is consistent with the centripetal acceleration view. The vanes can supply the centripetal force locally, instead of the entire force having to be transmitted from the outside of the elbow.

I found the velocity map on page 13 particularly interesting. It shows that the flows follow two counter-rotating helices around the curve.
can you explain, why the pressure at the outer wall of pipe is higher?
 
  • #18
foo9008 said:
can you explain, why the pressure at the outer wall of pipe is higher?
Do you understand that a centripetal force is needed to get the flow around the elbow?
 
  • #19
haruspex said:
Do you understand that a centripetal force is needed to get the flow around the elbow?
Yes
 
  • #20
foo9008 said:
Yes
So where will that force come from?
 
  • #21
haruspex said:
So where will that force come from?
the force of water to make the water to rotate around the bend ?
 
  • #22
foo9008 said:
the force of water to make the water to rotate around the bend ?
But something has to apply the force to the water.
 
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  • #23
haruspex said:
But something has to apply the force to the water.
so, how it relate to pressure at the outer and inner wall of bend?
 
  • #24
foo9008 said:
so, how it relate to pressure at the outer and inner wall of bend?
Consider a part of the flow that's adjacent to the outer wall. That gets a normal force from the wall to push it around the bend. Now consider a part next to that, just a bit further from the wall. At constant velocity it would run into the first part, creating a higher pressure. That higher pressure creates the normal force that pushes it also around the bend, and so on.
 
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  • #25
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  • #26
haruspex said:
Consider a part of the flow that's adjacent to the outer wall. That gets a normal force from the wall to push it around the bend. Now consider a part next to that, just a bit further from the wall. At constant velocity it would run into the first part, creating a higher pressure. That higher pressure creates the normal force that pushes it also around the bend, and so on.
do you mean higher pressure(normal forces) from the outer wall of the bend is required too keep the water to move around the bend (centripetal forces) ?
 
  • #27
haruspex said:
Consider a part of the flow that's adjacent to the outer wall. That gets a normal force from the wall to push it around the bend. Now consider a part next to that, just a bit further from the wall. At constant velocity it would run into the first part, creating a higher pressure. That higher pressure creates the normal force that pushes it also around the bend, and so on.
What do you mean by at constant velocity, it will run into the first part??
 
  • #28
foo9008 said:
do you mean higher pressure(normal forces) from the outer wall of the bend is required too keep the water to move around the bend (centripetal forces) ?
Yes.
foo9008 said:
What do you mean by at constant velocity, it will run into the first part??
According to Newton, in the absence of a net force, masses keep constant velocity, i.e. a constant speed in a constant direction. Think of the total flow as a number of separate parallel flows. The flow next to the wall is deflected by the normal force from the wall. The flow next to that, if not subjected to a net force, would keep going in a straight line and collide with the first flow. The tendency to do that raised the pressure. The resulting pressure gradient, from high next to the outer wall to low near the inner wall, provides the forces to deflect all these flows around the bend.
 
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  • #29
haruspex said:
Yes.

According to Newton, in the absence of a net force, masses keep constant velocity, i.e. a constant speed in a constant direction. Think of the total flow as a number of separate parallel flows. The flow next to the wall is deflected by the normal force from the wall. The flow next to that, if not subjected to a net force, would keep going in a straight line and collide with the first flow. The tendency to do that raised the pressure. The resulting pressure gradient, from high next to the outer wall to low near the inner wall, provides the forces to deflect all these flows around the bend.
Can you sketch a diagram showing the flow in pipe??
 
  • #30
foo9008 said:
Can you sketch a diagram showing the flow in pipe??
What's wrong with the diagrams on pages 13 and 14 of the SAND report linked from post #14? They give a very complete view.
The velocity map shows that two helical (corkscrew) flows arise, one in the top half and one in the lower half. Where they meet, both flows angle across from the inner wall towards the outer wall. When they reach the outer wall, the top half flows, at an angle, up the wall and loops back over the top towards the inner wall. Correspondingly, the lower half flow moves down the outer wall and loops back around the bottom of the pipe to the inner wall.
The flow across the halfway level, from inner wall to outer wall, is driven by momentum. The flow is against the pressure gradient and so is slowing down. Having reached the outer wall, and lost its momentum in that direction, the excess pressure there pushes the flow back around top and bottom curves to the inner wall again.
 
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  • #31
The flow of a fluid in a pipe bend can be anything from completely smooth to chaotic .

What actually happens depends on many things - such as bend geometry , flow velocity , fluid properties and initial flow pattern at entry .

Flow can also sometimes be unstable and in particular case of compressible fluids and high velocities shock waves can form .

Flow conditions can sometimes be improved by detail changes to pipe geometry . Some examples of this are : use of transition bend curvatures , return bulges and internal vanes .
 
  • #32
Nidum said:
The flow of a fluid in a pipe bend can be anything from completely smooth to chaotic .

What actually happens depends on many things - such as bend geometry , flow velocity , fluid properties and initial flow pattern at entry .

Flow can also sometimes be unstable and in particular case of compressible fluids and high velocities shock waves can form .

Flow conditions can sometimes be improved by detail changes to pipe geometry . Some examples of this are : use of transition bend curvatures , return bulges and internal vanes .
removed
 
  • #33
foo9008 said:
yes , i want to know how can L = ND ??

Could you explain what you mean please ?
 
  • #34
Nidum said:
Could you explain what you mean please ?
posted in wrong section , sorry
 

Related to What Causes Pressure Changes Along a Pipe?

1. What is the Bernoulli's principle and how does it relate to pressure changes along a pipe?

The Bernoulli's principle states that as the velocity of a fluid increases, its pressure decreases. This principle applies to pressure changes along a pipe because as the fluid flows through the pipe, its velocity changes and therefore, its pressure also changes.

2. What factors affect pressure changes along a pipe?

The main factors that affect pressure changes along a pipe are the fluid flow rate, the diameter of the pipe, and the fluid's viscosity. Other factors such as temperature, pipe material, and pipe length can also have an impact on pressure changes.

3. How does the shape of a pipe affect pressure changes?

The shape of a pipe can affect pressure changes in two ways. Firstly, a change in the pipe's diameter can cause a change in velocity, which in turn affects pressure. Secondly, the shape of the pipe can cause frictional losses, which can also impact pressure changes along the pipe.

4. How does gravity play a role in pressure changes along a pipe?

Gravity plays a role in pressure changes along a pipe by creating a pressure gradient. This means that as the fluid flows down a pipe, the pressure at the bottom will be higher than at the top. This is due to the weight of the fluid pressing down on itself.

5. How can pressure changes along a pipe be controlled?

Pressure changes along a pipe can be controlled by adjusting the flow rate, changing the pipe diameter, or using devices such as valves and pumps. Additionally, the use of fluid properties such as viscosity and density can also help control pressure changes along a pipe.

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