What determines a vacuum tube's perveance?

  • Thread starter EinsteinKreuz
  • Start date
  • Tags
    Current
In summary, a vacuum tube's perveance is determined by several factors, including the physical characteristics of the tube, such as its size and shape, the materials used, and the vacuum level inside the tube. Perveance is essentially a measure of the tube's ability to pass electrical current, and it is affected by the voltage applied to the tube and the distance between its electrodes. In general, a higher perveance indicates a more efficient and powerful vacuum tube, making it a crucial factor in designing and using these devices for various applications, from amplifiers to particle accelerators.
  • #1
EinsteinKreuz
64
1
So books on VT electronics are quite hard to come by these days and many electronics textbooks don't mention thermionic valves whatsoever. I managed to find a very good vintage book : Vacuum tube and semiconductor electronics(Millman, 1958).

It describes the triode plate current characteristic curve as defined by the equation:

[TEX] I_{A} = g_{m} = \sqrt{V_{G} + \frac {V_{A}{\mu}^{3} [/TEX]Where μ is the amplification factor and gm is the transconductance.

But another book defines IA = f(VA,VG) and expands it into a taylor series. Now first question is: Are the amplification factor and transconductance constant characteristics of the tube and if not, what are the independent variables which they depend on and how can they be calculated?

Also, is the first equation an aproximation? Because in another book it shows the triode current curves plotted against anode voltage for both negative grid voltages and one for positive grid voltage and when the grid is positive the curve has an inverted parabolic shape whereas when VG < 0 the curves are almost linear.

So in a nutshell, what's the best fit mathematical model of the triode anode current if you know the grid voltage function VG(t) and the voltage applied to the anode?
 
Engineering news on Phys.org
  • #2
All VTs are different. There is no single best approximation equation. Triodes are very rarely operated at fixed anode voltage. The characteristics of a VT change as it ages.

If you post the tube number and the available curves of the triode you intend to use, we may be able to help you.

Why do you need the approximation? Will you model a circuit with spice or use it in a numerical model?
See the PSpice model; http://www.duncanamps.com/spicevalvesgt.html
google 'spice triode model'

Have you got a copy of “Radiotron Designers Handbook”. Langford Smith. 4'th Edn. 1952. There are .pdf copies available.

Take a look at the MIT Radiation Laboratory Series. Series index is V28. .pdf are available from; http://www.jlab.org/ir//MITSeries.html
 
  • #3
EinsteinKreuz said:
So books on VT electronics are quite hard to come by these days and many electronics textbooks don't mention thermionic valves whatsoever. I managed to find a very good vintage book : https://www.amazon.com/dp/125832282X/?tag=pfamazon01-20

It describes the triode plate current characteristic curve as defined by the equation:

[TEX] I_{A} = g_{m} = \sqrt{V_{G} + \frac {V_{A}{\mu}^{3} [/TEX]Where μ is the amplification factor and gm is the transconductance.

But another book defines IA = f(VA,VG) and expands it into a taylor series. Now first question is: Are the amplification factor and transconductance constant characteristics of the tube and if not, what are the independent variables which they depend on and how can they be calculated?

Also, is the first equation an aproximation? Because in another book it shows the triode current curves plotted against anode voltage for both negative grid voltages and one for positive grid voltage and when the grid is positive the curve has an inverted parabolic shape whereas when VG < 0 the curves are almost linear.

So in a nutshell, what's the best fit mathematical model of the triode anode current if you know the grid voltage function VG(t) and the voltage applied to the anode?
There are useful formulas in Radio Engineers' Handbook, by Terman, one of which I will try to write for you:-
Ip = k(Eg+Ep/mu)^3/2. In this formula, k is a constant called the perveance - the ability of the device to pass current. The plate voltage is divided by mu, the amplification factor, as its influence on current is less than the grid by this factor. The tube constants depend on the geometry and on the electrode voltages. mu tends to be rather constant as voltages are altered, but Gm does not. The manufacturer usually gives standard operating voltages.
If going from negative to positive grid, there is no sudden change in the curvature of the mutual characteristic, but grid current will flow, so the grid circuit must have low resistance. If the grid positive voltage approaches Ep, then it suddenly robs the plate of electrons, and the Ep/Ip characteristic then saturates, or flat tops.
 
Last edited by a moderator:
  • #4

FAQ: What determines a vacuum tube's perveance?

What is the triode current equation?

The triode current equation is a mathematical equation used to calculate the current flowing through a triode vacuum tube. It takes into account factors such as the voltage applied to the tube, the tube's characteristics, and the resistance of the circuit.

What are the components of the triode current equation?

The triode current equation includes three main components: the plate current (Ip), the grid-to-cathode voltage (Vgk), and the plate voltage (Vp). These components are used to calculate the current flowing through the vacuum tube.

How is the triode current equation derived?

The triode current equation is derived from the laws of electricity and the characteristics of a vacuum tube. It takes into account Ohm's law, which states that current is directly proportional to voltage and inversely proportional to resistance.

What is the significance of the triode current equation?

The triode current equation is significant because it allows scientists and engineers to accurately predict the performance of a triode vacuum tube in a circuit. It is also a fundamental equation in understanding the behavior of electron tubes and has practical applications in electronics and telecommunications.

How is the triode current equation used in practical applications?

The triode current equation is used in many practical applications, such as in radio and television broadcasting, audio amplifiers, and electronic devices. It helps engineers design circuits and select appropriate vacuum tubes for specific applications, ensuring optimal performance and efficiency.

Back
Top