What Determines the Speed of the Second Puck After a Collision?

  • Thread starter Tabe
  • Start date
  • Tags
    Collisions
In summary, the problem involves a collision between two hockey pucks of equal mass, with one moving at 5.70 m/s and the other stationary. After the collision, the first puck moves at a 60 degree angle to the left of its original direction, while the second puck moves at a right angle to the first puck. To solve for the speed of the second puck, one must create a diagram of the collision, choose a coordinate system, write down the conservation of momentum and kinetic energy, and use Pythagorean theorem to find the speed.
  • #1
Tabe
42
0
Okay, here's the problem I'm working on...
A .50 kg hockey puck moving at a speed of 5.70 m/s collides with a stationary hockey puck of equal mass. After the collisions, the first puck moves off in a direction 60 degrees to the left of its original direction, while the second puck moves off at a right angle to the first puck. What is the speed of the second puck after the collision?
I know that I have to solve for the components, but I'm not sure which numbers to use to solve for it.
 
Physics news on Phys.org
  • #2
mmh... These are the "numbers":

initial horizontal momentum = (0.50 kg)(5.70)

initial vertical momentum = 0.
 
  • #3
1)Make a diagram of the particles which collide in which put the momentum vectors.Be careful with the angles.
2)Chose a coordinate system with the center in the collision point and 2 orthonorlmal axis.
3)Write down the conservation of momentum in vector form and conservation of KE.
4) Project the vector eq.written at 3) on the axis of coordinates.
5)Find the "speed of the second puck after the collision".Actually from 4) u find its components on the 2 axis of coordinates.Apply Pythagora's theorem to find the modulus.

Daniel.
 

FAQ: What Determines the Speed of the Second Puck After a Collision?

What is the physics behind collisions of hockey pucks?

The physics behind collisions of hockey pucks involves the principles of conservation of momentum and conservation of energy. When two pucks collide, the total momentum of the system remains the same before and after the collision. The kinetic energy of the system, however, may change depending on the type of collision (elastic or inelastic).

How do different factors affect the outcome of a collision between hockey pucks?

Factors such as the mass, velocity, and angle of collision between hockey pucks can greatly affect the outcome of a collision. The type of surface the pucks are on, such as ice or a rough playing surface, can also impact the collision. Additionally, the elasticity of the pucks and any external forces, like friction, can also play a role.

What is an elastic collision between hockey pucks?

An elastic collision between hockey pucks is a collision where the total kinetic energy of the system is conserved. This means that the pucks bounce off each other with no loss of energy. In an elastic collision, the momentum and velocity of each puck may change, but the total kinetic energy of the system remains the same.

What is an inelastic collision between hockey pucks?

An inelastic collision between hockey pucks is a collision where the total kinetic energy of the system is not conserved. This means that some of the kinetic energy is lost during the collision, usually in the form of heat or sound. In an inelastic collision, the pucks may stick together after the collision, resulting in a decrease in velocity for both pucks.

How can the principles of collisions be applied in the game of hockey?

The principles of collisions can be applied in hockey to predict the outcome of a collision between players or between a player and the boards. This can help players make strategic moves to gain an advantage over their opponents. The understanding of collisions can also aid in the design and development of safer equipment for players.

Back
Top