- #1
Tzabcan
- 10
- 0
I have this basic differential equation du/dt=(u^2)*(sin t)
This is obviously a separable diff eq.
So what I've done is:
g(t) = sin t h(u) = u^2
1/(u^2) du = sin t dt
Integrating both side...
1/y = - cos t + c
therefor y = - 1/(cos t + c)Which is wrong, there isn't supposed to be a minus sign apparently. I don't know what I've done wrong. Any suggestions? Thanks.
This is obviously a separable diff eq.
So what I've done is:
g(t) = sin t h(u) = u^2
1/(u^2) du = sin t dt
Integrating both side...
1/y = - cos t + c
therefor y = - 1/(cos t + c)Which is wrong, there isn't supposed to be a minus sign apparently. I don't know what I've done wrong. Any suggestions? Thanks.