- #1
Newphysicsguy
- 3
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Find [itex]\vec{a}+\vec{b}[/itex] (Look at the picture)
The book shows the solutions as :
a. 4.1m Along the +x axis.
I however do not know where I went wrong in my calculations.
[itex]\vec{a}+\vec{b}=\begin{bmatrix}
a_x+b_x\\
a_y+b_y
\end{bmatrix}=\begin{bmatrix}
|\vec{a}|\cos(30)+|\vec{b}|\cos(45)\\
|\vec{a}|\sin(30)-|\vec{b}|\sin(45)
\end{bmatrix}=\begin{bmatrix}
\frac{3\sqrt{3}}{2}+\sqrt{2}\\
1.5-\sqrt{2}
\end{bmatrix}=\begin{bmatrix}
4.01\\
.085
\end{bmatrix}[/itex]NOTE: If I posted this is the wrong location I am sorry. This is not homework, I am doing it on my own time.
EDIT: thank you for moving my post to the correct location.
The book shows the solutions as :
a. 4.1m Along the +x axis.
I however do not know where I went wrong in my calculations.
[itex]\vec{a}+\vec{b}=\begin{bmatrix}
a_x+b_x\\
a_y+b_y
\end{bmatrix}=\begin{bmatrix}
|\vec{a}|\cos(30)+|\vec{b}|\cos(45)\\
|\vec{a}|\sin(30)-|\vec{b}|\sin(45)
\end{bmatrix}=\begin{bmatrix}
\frac{3\sqrt{3}}{2}+\sqrt{2}\\
1.5-\sqrt{2}
\end{bmatrix}=\begin{bmatrix}
4.01\\
.085
\end{bmatrix}[/itex]NOTE: If I posted this is the wrong location I am sorry. This is not homework, I am doing it on my own time.
EDIT: thank you for moving my post to the correct location.
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