What Do the Derivatives and Graphs Reveal About y=(2x+1)/\sqrt{x^2+1}?

  • Thread starter Thread starter Hurricane3
  • Start date Start date
  • Tags Tags
    Derivatives Graphs
Click For Summary
The discussion focuses on analyzing the function y=(2x+1)/√(x^2+1) to determine its asymptotes and behavior. The first derivative calculated is dy/dx = (2x^2 - x + 2)/((x^2 + 1)√(x^2 + 1)), which reveals no roots, indicating there are no vertical asymptotes since x^2 + 1 cannot equal zero. There are also no horizontal asymptotes, as the function approaches a constant value. The analysis suggests that the function either always increases or always decreases, as it lacks any horizontal line segments. Overall, the function's behavior is characterized by its continuous increase or decrease without any asymptotic interruptions.
Hurricane3
Messages
16
Reaction score
0

Homework Statement



y=(2x+1)/\sqrt{x^2+1}

Find where are the asymptotes, where is it increasing increasing/decreasing, ect...

Homework Equations





The Attempt at a Solution


when I took the first derivative (im trying to find where it increases/decrease), I got
dy/dx = \frac{2x^2-x+2}{(x^2+1)\sqrt{x^2+1}}

but there isn't any roots for this function... so what does that mean?
 
Last edited:
Physics news on Phys.org
No vertical asymptotes as x^2+1 can never be 0.

No horizontal asy as (x^2)^1/2 is one, and 2x is one.

Slant asymptote is synthetic division (x^2+1)^(1/2) |2x+1

If there are no 0's then that means that the equation always increases or decreases.
 
Grammer police: Better would be "either always increases or always decreases".


Any graph that does not have a horizontal line segment "always increases or decreases"!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 105 ·
4
Replies
105
Views
6K
Replies
4
Views
2K
Replies
9
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 21 ·
Replies
21
Views
2K