haruspex said:@Orodruin has explained to me that the point being considered is on the x axis. Consequently ##\vec E_y=\vec E_z=0## is consistent with the field being normal to the cylinder's axis. What made you think it was not?
The y axis is also normal to the cylinder's axis...haruspex said:The field is everywhere normal to the cylinder axis
Yes, ##\vec E(x\hat x)=f(x)\hat x##, so no ##\hat y## or ##\hat z## term.tellmesomething said:The y axis is also normal to the cylinder's axis...
But I think I get it it also depends on where the reference point is...so