- #1
Aerodfocker
- 1
- 0
In the case of inverted pendulum attached in a cart with external force U on it,
the equation of motion is like
U - mg(theta1) - mg(theta2) = m*dv/dt
I don't really understand the mg*theta part what does it mean ...should not be sine or cosine fn there with theta ?
can anyone give me some insight on this
thanks in advance ...really appreciate it.
p.s. I HAVE ATTACHED THE FULL QUESTION HERE AS WELL
the equation of motion is like
U - mg(theta1) - mg(theta2) = m*dv/dt
I don't really understand the mg*theta part what does it mean ...should not be sine or cosine fn there with theta ?
can anyone give me some insight on this
thanks in advance ...really appreciate it.
p.s. I HAVE ATTACHED THE FULL QUESTION HERE AS WELL