What does off-diagonal term mean?

  • Thread starter physlad
  • Start date
  • Tags
    Mean Term
In summary, applying the Higgs mechanism to the Lagrangian of a complex scalar field leads to the generation of terms for a Goldstone boson, a massive scalar, and a massive vector field. This also reveals that the original Lagrangian does not describe physical fields, and must be rewritten in terms of real fields to obtain the desired massive vector and scalar particles.
  • #1
physlad
21
0
when we apply Higgs mechanism to the lagrangian of a complex scalar field... we get terms for a Glodstone boson, a massive scalar and a massive vector field in the new lagrangian..

we also get other terms.. one of them takes following form

[tex] A_\mu \partial^\mu \xi [/tex]

this term is said to be off-diagonal in the fields... what does this mean? and what does it imply?

I mean how can we know just by looking at such a term that our lagrangian does not describe physical fields? and that we need to rewrite the lagranigan in terms of real fields... until we get the lagrangian which contains a massive vector and a massive scalar (Higgs particle)..

:confused:
 
Last edited:
Physics news on Phys.org
  • #2
The term you mentioned is off-diagonal because it involves two distinct fields, the vector field A_μ and the scalar field ξ. This implies that the Lagrangian does not contain physical fields describing a massive vector and massive scalar (Higgs particle), and must be rewritten in terms of real fields. This is done by introducing a unitary transformation on the scalar fields, which allows us to write the original complex scalar field as a combination of two real scalar fields. The same transformation can then be applied to the vector field, resulting in a massive vector and a massive scalar (the Higgs particle).
 
  • #3


The off-diagonal term in this context refers to a term in the Lagrangian that involves two different fields, in this case the vector field A and the Goldstone boson field \xi. This term is called off-diagonal because it does not involve just one field, but a combination of two fields.

The presence of this off-diagonal term implies that the Lagrangian does not describe physical fields in a straightforward way. This is because the Lagrangian should only involve terms that correspond to physical particles that can be observed in experiments. The off-diagonal term indicates that the fields A and \xi are not the physical fields, and that we need to rewrite the Lagrangian in terms of other fields that correspond to observable particles.

In this case, the Higgs mechanism is used to rewrite the Lagrangian in terms of real fields, which correspond to the massive scalar and vector fields that can be observed in experiments. This is why the off-diagonal term is important - it allows us to identify the fields that are not physical and to rewrite the Lagrangian in terms of the physical fields.
 

FAQ: What does off-diagonal term mean?

What does the off-diagonal term in a matrix represent?

The off-diagonal term in a matrix represents the elements that are not on the main diagonal. These elements are located above or below the main diagonal of the matrix.

Why is the off-diagonal term important in matrix operations?

The off-diagonal term is important in matrix operations because it affects the outcome of the matrix calculation. It represents the interaction between different variables in the matrix and can impact the overall result of the operation.

How is the off-diagonal term used in eigenvalue calculations?

In eigenvalue calculations, the off-diagonal term is used to determine the relationship between the eigenvectors and eigenvalues of a matrix. It is used to transform the original matrix into a diagonal matrix, making it easier to find the eigenvalues.

What is the difference between an off-diagonal term and a diagonal term?

An off-diagonal term is an element in a matrix that is not on the main diagonal, while a diagonal term is an element that is on the main diagonal. The diagonal terms represent the main variables in the matrix, while the off-diagonal terms represent the interactions between those variables.

Can the off-diagonal term be zero?

Yes, the off-diagonal term can be zero. This means that there is no interaction between the variables represented by the corresponding rows and columns in the matrix. In other words, the variables are not dependent on each other.

Similar threads

Replies
1
Views
1K
Replies
3
Views
1K
Replies
3
Views
4K
Replies
2
Views
2K
Replies
4
Views
1K
Replies
11
Views
1K
Replies
3
Views
2K
Replies
2
Views
1K
Replies
4
Views
679
Back
Top