What Does the [A., A.] Term Signify in Non-Abelian Yang-Mills Theory?

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In summary, the conversation discussed the complementary term [A., A.] in the yang Mills formulation of the EM field tensor and its physical interpretation in relation to the non-Abelian nature of the theory. The definition of this term and its interpretation as self-coupling between gauge bosons were also mentioned. The conversation also touched upon the different interpretations and proposals for this term in the literature, and the speaker's own research on a new formulation of the tensor using a new mathematical operation and parallel transport of the A vector. The speaker expressed their gratitude for the help and clarification provided.
  • #1
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In the yang Mils formulation of the EM field (Faraday Maxwell) tensor, what exactly is (means) the complementary term usually written: [A., A.] (see for example the article of Jackiw: 50 years of the Yang Mils theory and my contribution to it) and related to the fact that this theory can be non Abelian? Thanks for your help
 
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  • #2
Blackforest said:
In the yang Mils formulation of the EM field (Faraday Maxwell) tensor, what exactly is (means) the complementary term usually written: [A., A.] (see for example the article of Jackiw: 50 years of the Yang Mils theory and my contribution to it) and related to the fact that this theory can be non Abelian? Thanks for your help
I am not sure what your question is exactly (do you want to know what the *definition* of this expression is? Or what is the physical interpretation?).

The gauge fields are in the adjoint representation (they are of the form [itex] A_\mu^a \lambda_a [/itex] where the lambda's are the generators of the group. Since the group is non abelian, the commutator does not vanish.

The physical interpretation is that there is self-coupling between the gauge bosons. There is no direct coupling between two photons (because QED is abelian) but there *is* self coupling between gluons or between W's and Z bosons.
 
  • #3
nrqed said:
I am not sure what your question is exactly (do you want to know what the *definition* of this expression is? Or what is the physical interpretation?).

The gauge fields are in the adjoint representation (they are of the form [itex] A_\mu^a \lambda_a [/itex] where the lambda's are the generators of the group. Since the group is non abelian, the commutator does not vanish.

The physical interpretation is that there is self-coupling between the gauge bosons. There is no direct coupling between two photons (because QED is abelian) but there *is* self coupling between gluons or between W's and Z bosons.

Thanks for your rapid answer. My initial question was about the definition of the brackets. In another article concerning the anomalies and the renormalization of the BF YM theory, a new formulation of this term appears. The proposition for it is a quadratic form of the components of the EM field potential vector (the A 4-vector). I am working myself about a reformulation of this tensor and that was the reason of my question (see independant research forum and my home page). I recently did success to get a new expression of the tensor assuming the existence of a "new" mathematical operation (the extended vector product) and assuming a parallel transport of this A vector by respect for the trajectory. I don't know if it owns a physical signification but the formalism looks interesting.
 
  • #4
To be clear: my question is not to make publicity for my own and insignifiant research but only motivated by the fact that it seems to exist several propositions and interpretations in the litterature for this complementary term. I was lost. I just try to understand better. The physical interpretation that you give (self coupling between gluons) takes a particular relief when it is confronted with my own calculations which are absolutely not complicated but which are implying a special lecture of the usual formulation of the tensor. Once more time thanks for your help and that was.
 

FAQ: What Does the [A., A.] Term Signify in Non-Abelian Yang-Mills Theory?

What is Yang Mills theory?

Yang Mills theory is a theoretical framework in physics that describes the behavior of elementary particles, specifically the strong nuclear force between quarks. It is based on the idea of gauge symmetry, which is a mathematical concept that describes the invariance of physical laws under certain transformations.

Why is Yang Mills theory important?

Yang Mills theory is important because it provides a mathematical framework for understanding the behavior of fundamental particles and their interactions. It has been successfully used to explain the strong nuclear force and has also been used as a basis for developing other theories, such as the Standard Model of particle physics.

What is the difference between Yang Mills theory and quantum chromodynamics (QCD)?

Yang Mills theory is a general framework for describing the strong nuclear force, while QCD is a specific theory within this framework that describes the interactions between quarks and gluons. Yang Mills theory is more general and can be applied to other systems, while QCD is specifically focused on the strong nuclear force.

What is the current status of Yang Mills theory in the field of physics?

Yang Mills theory is still an active area of research in physics. While it has been successfully applied to explain the strong nuclear force, there are still unresolved questions and challenges within the theory. Researchers are also exploring its potential applications in other areas, such as condensed matter physics and quantum computing.

Are there any practical applications of Yang Mills theory?

While Yang Mills theory is primarily used as a theoretical framework in physics, it has also been applied in other fields. For example, it has been used in theoretical studies of quantum computing and has also been applied in some areas of mathematics, such as differential geometry and topology.

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