- #36
ghwellsjr
Science Advisor
Gold Member
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Exactly and that's because the ratio between ct and st is the same for all t. You just have a different size triangle involving ct, st and vt. I just don't know why you think there is anything significant for the specific value of t corresponding to when the photons hit U's mirror. If you had used the value of t corresponding to when the photons hit A's mirror, then st will be equal to r, the distance to U's mirror from O, and ct would be the distance to A's mirror from O, and ct/st = c/s = gamma. If you would draw that diagram, which is the diagram that everyone else draws, then it seems like it would be more helpful to those new to SR.phyti said:If the path is extended, it will not show anything new. Gamma is still the ratio c/s or (A time)/(U time).