- #1
Hypnos_16
- 153
- 1
Homework Statement
A hiker, who weighs 986 N, is strolling through the woods and crosses a small horizontal bridge. The bridge is uniform, weighs 3550 N, and rests on two concrete supports, one at each end. He stops one-fifth of the way along the bridge. What is the magnitude of the force that a concrete support exerts on the bridge at the near end
Weight of Person = 986N
Weight of Bridge = 3550N
d = 1/5th of Bridge length
Homework Equations
This is a torque question, so the equation is T = F x d
i know that the force is the person times gravity, but that's already done.
However i don't know the length of the bridge, I've tried dividing the mans mass by 5 and adding that to the bridge's weight, but to no prevail. i really need some help here guys
The Attempt at a Solution
no really attempts
T = 986 x 0.2
T = 197.2
T = 197.2 + 3550
T = 3747.2