kirby2 said:A charge q and a charge 3q are released in a uniform electric field. If the force this field exerts on 3q is F, the force it will exert on q is:
i think the answer is F/3. is this right? i used E=F/q.
A uniform electric field is a type of electric field in which the magnitude and direction of the electric field strength is constant at all points within the field. This means that the strength and direction of the electric field does not vary from one point to another.
A uniform electric field can be created by placing two parallel plates with opposite charges (positive and negative) close to each other. The electric field between these plates will be uniform as long as the plates are large enough and the distance between them is small.
The strength of a uniform electric field can be calculated by dividing the magnitude of the electric field by the distance between two points in the field. This is known as the electric field strength or electric field intensity. The unit for electric field strength is volts per meter (V/m).
In a uniform electric field, the direction of the electric field is the same at all points within the field. It is always perpendicular to the surface of the charged plates and points from the positive plate towards the negative plate.
Uniform electric fields have many practical applications, such as in particle accelerators, cathode ray tubes, and air ionizers. They are also used in electrostatic precipitators to remove pollutants from industrial exhaust gases, and in capacitors for energy storage.