What fraction of light do these glasses transmit

In summary: So T= antilog(-39/7). (Or raise 10 to the (-39/7) power)In summary, welders use a logarithmic scale to identify protective eyewear, with the shade number n being determined by the equation n = 1 − (7log(T))/3, where T is the fraction of visible light that glass transmits. For a welder who wants to only transmit ⅛ of the light entering the glass, they should use a shade number of 1- (7 log(1/8))/3. Viewing a solar eclipse through #14 welding glasses is considered safe, which means that these glasses transmit a fraction of light determined by the equation T= antilog(-39
  • #1
fxacx
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Welders use a logarithmic scale to identify protective eyewear. The shade number n, is given by the
equation n = 1 − 7logT/3 , where T is the fraction of visible light that glass transmits.

a. What shade number should a welder use that only transmits ⅛ of the light entering the glass?
b Viewing a solar eclipse through #14 welding glasses is considered safe. What fraction of light do
these glasses transmit.
 
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  • #2
fxacx said:
Welders use a logarithmic scale to identify protective eyewear. The shade number n, is given by the
equation n = 1 − 7logT/3 , where T is the fraction of visible light that glass transmits.

a. What shade number should a welder use that only transmits ⅛ of the light entering the glass?
b Viewing a solar eclipse through #14 welding glasses is considered safe. What fraction of light do
these glasses transmit.

is the equation $n=1-7\log \left(\dfrac{T}{3}\right)$ ... ?

please confirm
 
  • #3

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  • #4
fxacx said:
Welders use a logarithmic scale to identify protective eyewear. The shade number n, is given by the
equation n = 1 − (7log(T))/3 , where T is the fraction of visible light that glass transmits.

a. What shade number should a welder use that only transmits ⅛ of the light entering the glass?
So T= 1/8. n= 1- (7 log(1/8))/3. Can you do the arithmetic?

b. Viewing a solar eclipse through #14 welding glasses is considered safe. What fraction of light do these glasses transmit.
Now n= 14 so 14= 1- (7 log(T))/3. 14- 1= 13= -(7/3) log(T).
-(3/7)(13)= -39/7= log(T). Do you know how to "reverse" log?
 
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FAQ: What fraction of light do these glasses transmit

What fraction of light do these glasses transmit?

The fraction of light that these glasses transmit depends on the specific type of glasses and their level of tint or darkness. Generally, glasses can transmit anywhere from 10-90% of light, with darker glasses transmitting less light and lighter glasses transmitting more light.

How is the fraction of light transmitted by glasses measured?

The fraction of light transmitted by glasses is typically measured using a spectrophotometer, which measures the amount of light that passes through the glasses at different wavelengths. This data is then used to calculate the overall fraction of light transmitted by the glasses.

What factors affect the fraction of light transmitted by glasses?

The main factors that affect the fraction of light transmitted by glasses are the material and thickness of the glasses, the level of tint or darkness, and any coatings or filters applied to the glasses. Additionally, the angle of incidence and the type of light (e.g. visible light, UV light) can also impact the fraction of light transmitted.

Can the fraction of light transmitted by glasses be changed?

Yes, the fraction of light transmitted by glasses can be changed by altering the tint or darkness of the glasses, or by applying coatings or filters to the glasses. Additionally, different materials and thicknesses of glasses can also affect the fraction of light transmitted.

Why is it important to know the fraction of light transmitted by glasses?

Knowing the fraction of light transmitted by glasses is important for a variety of reasons. It can impact the clarity and quality of vision for the wearer, as well as the level of protection provided against UV rays. It can also be important for specific activities, such as driving or working with sensitive equipment, where certain levels of light transmission may be necessary.

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