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Tom_Greening
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Hello, I'm new to this forum. I hope I am submitting this to the right thread.
Just started physics and I am looking to get a little assistance
A single loop carries 100mA and has an inductance of 100μH
For air cored
L = μ0 * (N^2*A/length)
L = Nø/i
What is the inductance in each case?
a)What happens to inductance when the current is increased to 200mA? And what is the flux through loop?
b)What happens to inductance when the current is increased to 400mA and there are two loops, what is the flux through loop?
c)What happens to inductance when the current is set to 100mA and four loops, what is the flux through loop?
There is 100mA and one loop = 100μH
Then
L = Nø / i
100μH = 1 turn*ø / 0.1A, therefore flux is equal to = 1x10-6
a) If I increase the current to 200mA then the inductance will be half based on formula.
1 turn*ø / 0.2A = 50μH, the flux remains the same = 1x10-6
b) If I increase the current to 400mA and there are two loops then I've effectively doubled the length, Area remains the same, but how do I calculate to new inductance and flux?c) If I leave the current at the original 100mA and put four loops, then I would multiply the inductance by 4 to get 400μH
I'm new to this and i am not sure if I am getting it right.
Many thanks
Tom
Just started physics and I am looking to get a little assistance
Homework Statement
A single loop carries 100mA and has an inductance of 100μH
Homework Equations
For air cored
L = μ0 * (N^2*A/length)
L = Nø/i
What is the inductance in each case?
a)What happens to inductance when the current is increased to 200mA? And what is the flux through loop?
b)What happens to inductance when the current is increased to 400mA and there are two loops, what is the flux through loop?
c)What happens to inductance when the current is set to 100mA and four loops, what is the flux through loop?
The Attempt at a Solution
There is 100mA and one loop = 100μH
Then
L = Nø / i
100μH = 1 turn*ø / 0.1A, therefore flux is equal to = 1x10-6
a) If I increase the current to 200mA then the inductance will be half based on formula.
1 turn*ø / 0.2A = 50μH, the flux remains the same = 1x10-6
b) If I increase the current to 400mA and there are two loops then I've effectively doubled the length, Area remains the same, but how do I calculate to new inductance and flux?c) If I leave the current at the original 100mA and put four loops, then I would multiply the inductance by 4 to get 400μH
I'm new to this and i am not sure if I am getting it right.
Many thanks
Tom
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