- #1
subhradeep mahata
- 120
- 13
Homework Statement
The above circuit shows two cells of emfs E1 and E2 and two resistors with resistances R1 and R2. If E2 is short circuited, then what is the current through R1?
Homework Equations
The Attempt at a Solution
First of all, i am not sure what it exactly means when a cell is short circuited, but i suppose it means no current flows through E2. Going by this notion, first we consider the case where nothing is short circuited and everything is normal. Then, i will apply KVL in three loops as:
In outer loop clockwise:
E1-R1i+E2=0
or, E1+E2=R1i .....(1)
Inner left loop clockwise:
E1-R1i-R2i1=0
or, E1=R1i+R2i1 .....(2)
Inner right loop clockwise:
E2+R2i1=0
or, E2=-i1R2 ......(3)
Now, from (3): i1= -E2/R2 ...(4)
from (1): i=(E1+E2)/R1 ...(5)
So, i-i1= {R2(E1+E2)}/R1R2 (Lets call this x)
The final circuit looks something like this:
Now, according to question, x=0.
So, on solving, we get E1+E2=-E2R1/R2
Substituting this in (5), we get i= -E2/R2
That's my final answer, but my books says the correct answer is E1/R1
Also, my teacher said that since no current flows through E2, the circuit has only E1, R1 and R2. So, required current= E1/R1+R2
I am terribly confused, Please help me out.