What happens when you enter a black hole

In summary: No. According to the book Quantum Fields in Curved Space by Birrell and Davies, pages 268-269,These consideration resolve an apparent paradox concerning the Hawking effect. The proper time for a freely-falling observer to reach the event horizon is finite, yet the free-fall time as measured at infinity is infinite. Ignoring back-reaction, the black hole will emit an infinite amount of radiation during the time that the falling observer is seen, from a distance to reach the event horizon. Hence it would appear that, in the falling frame, the observer should encounter an infinite amount of radiation in a finite time, and so be destroyed. On the other hand, the event horizon is a global construct, and has no local
  • #36
bm0p700f said:
So for a moving observer there is a density increase. Density and the gravitational field strength that results are linked. So a black hole could form in that respect.
A http://math.ucr.edu/home/baez/physics/Relativity/BlackHoles/black_fast.html" . GoodPR has yet to provide any evidence, logic, or math in support of his position, instead relying entirely on stubborn determination to ignore and misunderstand everything anyone else says. It is simply wrong, it has been refuted by reputable sources, by theoretical considerations, and by experimental observation (high energy cosmic rays do not form black holes).
 
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  • #37
I just want to add to post #33 the following extracted from wiki talk-

'The only time kinetic energy shows up as increased gravitational field is when it's the kinetic energy in a SYSTEM where the sum of momenta is zero. Otherwise, kinetic energy shows up.. ..as increased momentum, but not as gravity.'

which I think shed more light on the subject of KE as gravity or momentum.

While it's already been proved that objects at high speed increase in mass/energy (as in the LHC, the sum mass of the particles produced is approx. equal to the KE + rest mass of the particles collided), it would be interesting to know how the gravitational field of these objects is affected at high speed.
 
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  • #38
  • #39
Different ACCELERATED frames do not agree on the number of real (non-virtual) particles. Virtual particle in one frame can become a real one in another accelerated frame and vs AFAIK the Hawking radiation is based on that fact.

Virtual particles are not observeable to a stationary observer. A free falling observer will pass the horizon of a black hole as virtual particles invisibly flash in and out of momentary existence harmlessly around him; a stationary observer outside the black hole horizon will be fried by those former virtual particles that now appear as REAL particles exhibiting thermal energy.
 
  • #40
When you enter a black hole, you get ripped apart by the shear force of the gravitational field. Also, black holes could be considered not part of the rest of the universe because space-time is altered so much that time literary stops theoretically.

Here is an interesting point. Let's say you are just outside the black hole, before the event horizon so you don't get pulled in and you throw a rock into the black hole. What you will see is the rock heading towards the black hole then eventually slow down and come to a stop. You will see the rock just "floating" in the black hole. Because space-time is skewed so much, you will see the rock frozen in time while the rock is actually ripping apart in the black hole. Good old theory of relativity.
 
  • #41
dream431ca said:
When you enter a black hole, you get ripped apart by the shear force of the gravitational field. Also, black holes could be considered not part of the rest of the universe because space-time is altered so much that time literary stops theoretically.

What a nice collection of misconseptions about black holes!
Tidal forces are not infinite at the horizon. For very heavy black holes these forces can be quite small so humans can survive
Also, GR insists that BH *is* a part of our space time (and for that very re4ason it can calculate what is inside)
"times stops" is WRONG. I recommend checking space time diagrams to really understand what is inside.
 
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