MHB What happens when you expand and factor (a + b + c)^3 - a^3 - b^3 - c^3?

  • Thread starter Thread starter mathdad
  • Start date Start date
  • Tags Tags
    Factoring
AI Thread Summary
To factor the expression (a + b + c)^3 - a^3 - b^3 - c^3, the initial step involves expanding (a + b + c)^3. This allows for the cancellation of the terms -a^3, -b^3, and -c^3. The problem can be approached by rewriting it as the difference of cubes for [(a + b + c)^3 - a^3] and the sum of cubes for [b^3 + c^3]. Applying these methods will lead to significant term cancellations. Ultimately, the goal is to simplify the expression effectively through these algebraic identities.
mathdad
Messages
1,280
Reaction score
0
Factor the expression.

(a + b + c)^3 - a^3 - b^3 - c^3

I believe the best way to tackle this problem is to expand (a + b + c)^3. By doing so, I should be able to cancel out -a^3 - b^3 - c^3, right?
 
Last edited:
Mathematics news on Phys.org
RTCNTC said:
Factor the expression.

(a + b + c)^3 - a^3 - b^3 - c^3

I believe the best way to start problem is by expanding
(a + b + c)^3. By doing so, I should be able to cancel out
-a^3 - b^3 - c^3, right?
Start by writing it as $[(a+b+c)^3 - a^3] - [b^3 + c^3]$, and factor the contents of each of the square brackets as the difference (or sum) of two cubes.
 
The difference of cubes is applied to
[(a + b + c)^3 - a^3] and the sum of cubes to [b^3 + c^3].

Correct?
 
RTCNTC said:
The difference of cubes is applied to
[(a + b + c)^3 - a^3] and the sum of cubes to [b^3 + c^3].

Correct?
Yes! What happens when you do that?
 
Opalg said:
Yes! What happens when you do that?

I have not completed the problem. So, my guess is that after applying the sum and difference of cubes, lots of terms will get canceled in the process.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Back
Top