- #1
gijungkim
- 50
- 2
Homework Statement
The graph below shows how the force on a 0.500 kg particle varies with position. If the particle has speed https://www.physicsforums.com/x-apple-ql-id://92193C91-FD4D-4A2B-AE3A-A915237F9B1D/x-apple-ql-magic/4C0641E9-916A-4CAB-8E8F-A20E6CE7E040.pdf at x = 2.00 m, what is its speed in m/s when x = 8.00 m?
Have a picture
Homework Equations
KE = 0.5m*vf^2 - 0.5 m*vi^2
W = F * d
The Attempt at a Solution
So what I basically did was to get an area of the graph because it will be F * d. After getting an area (work) I assumed that I could use KE equation like
KE = 0.5m*vf^2 - 0.5 m*vi^2 = 51J
Then I got Vf as 14.5m/s. However, the answer is 15.0 m/s. Can anyone help me what I did wrong here?
Attachments
Last edited by a moderator: