What is \mathbb{C}(x) and why is it not algebraically closed?

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In summary: So in this case, F(a) is equivalent to the field of rational functions in a over F.In summary, \mathbb{C}(x) (\mathbb{C} adjoined with x) is not algebraically closed because it is the field of quotients of polynomials with complex coefficients, and not just polynomials with complex coefficients. The notation \mathbb{C}(x) is different from \mathbb{C}(a), where a can be algebraic or transcendental. Additionally, if E is a field extension of F, and a is algebraic over F, if b is in F(a), then F(b) is a subfield of F(a).
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Why is it that [tex]\mathbb{C}(x)[/tex] ([tex]\mathbb{C}[/tex] adjoined with x) is not algebraically closed? Here x is an indeterminate.

My first question is what does the field extension [tex]\mathbb{C}(x)[/tex] even mean? If E is a field extension of F, and a is an transcendental element of E over F, then the notation [tex]\mathbb{C}(a)[/tex] is defined to mean the field of quotients of [tex]\mathbb{C}[a][/tex] (set of polynomials with complex coefficients). If a is algebraic then [tex]\mathbb{C}(a)[/tex] is defined to be [tex]\mathbb{C}[a][/tex] (which is the same thing as the field of quotients of [tex]\mathbb{C}[a][/tex], since in this case [tex]\mathbb{C}[a][/tex] is a field).

Now x is an indeterminate, is that the algebraic or transcendental case? i.e. does [tex]\mathbb{C}(x)[/tex] mean field of quotients of polynomials with complex coefficients, or does it mean just polynomials with complex coefficients.

So apparently [tex]\mathbb{C}(x)[/tex] is somehow not algebraically closed. So is there a complex polynomial whose root isn't a complex number? Any help is greatly appreciated.
 
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[tex]\mathbb{C}(x)[/tex] has to be field of quotients, because it has to be a field.

It's not a complex polynomial. It's a polynomial with coefficients in [tex]\mathbb{C}(x)[/tex]. (note these will NOT be polynomials in x). For example:

[tex]p(y)=x^4y^2 + (3x^2-\frac{2}{x})y + \frac{3}{x}[/tex]

is a quadratic polynomial. The question is whether you can find a solution [tex] y \in \mathbb{C}(x)[/tex]
 
  • #3
So the notation [tex]\mathbb{C}(x)[/tex] isn't related to the notation [tex]\mathbb{C}(a)[/tex], where a is algebraic or transcendental?

Hmm I thought field of quotients meant something in the form p(x)/q(x) i.e. has elements like:
[tex]\frac{2ix^2 -3}{4i-x}[/tex].
So this isn't right either?

Also, while on the subject of field extensions, why is it that: if E is a field extension of F, and a in E is algebraic over F, if b in F(a) then F(b) is a subfield of F(a).
 
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What do you have for your definition for [tex]F(a)[/tex] if F is a field?
 
  • #5
Office_Shredder said:
What do you have for your definition for [tex]F(a)[/tex] if F is a field?

If F is a field, then F[a] would be the set of all polynomials in a, (i.e. a typical element would be b_n * a^n + ... + b_1 * a + b_0 where all the b_ i in F), then F(a) is defined to be the field of quotients of F[a].
 

FAQ: What is \mathbb{C}(x) and why is it not algebraically closed?

What is algebraic closure?

Algebraic closure is a concept in abstract algebra that refers to the process of extending a field (a set of numbers with operations like addition and multiplication) to include all of the roots of all of its polynomial equations. Essentially, it allows for the solution of polynomial equations with coefficients in the field.

Why is algebraic closure important?

Algebraic closure is important because it allows for the solution of polynomial equations, which are used in many areas of mathematics and science. It also helps to simplify and clarify the structure of fields and their extensions.

What is the difference between algebraic closure and algebraic extension?

The main difference between algebraic closure and algebraic extension is that algebraic closure refers to extending a field to include all of the roots of all polynomial equations, while algebraic extension refers to extending a field to include the roots of one specific polynomial equation.

How is algebraic closure related to Galois theory?

Galois theory is a branch of mathematics that studies field extensions. Algebraic closure is related to Galois theory because it helps to classify and understand the structure of fields and their extensions, which is a key aspect of Galois theory.

What are some applications of algebraic closure?

Algebraic closure has many applications in mathematics and science, including number theory, algebraic geometry, and physics. It is also used in cryptography and coding theory, as well as in the study of differential equations and dynamical systems.

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