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adf89812
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- TL;DR Summary
- AO energy difference maximum such that bonding orbital is still possible is what?
>-Atomic orbitals must be at the similar energy levels to combine as molecular orbitals, said Wikipedia.
This is unclear. How do you quantify how "similar" means?
I heard electronegative is tied to atomic radius is tied to atomic orbital energy.
What are two atoms that would in theory form an ionic compound if you use a naive theory but actually don't because the atomic orbitals are too dissimilar in energy levels according to molecular orbital theory?
>The essential point of Pauling electronegativity is that there is an underlying, quite accurate, semi-empirical formula for dissociation energies, namely:
>$$
E_{\mathrm{d}}(\mathrm{AB})=\frac{E_{\mathrm{d}}(\mathrm{AA})+E_{\mathrm{d}}(\mathrm{BB})}{2}+\left(\chi_{\mathrm{A}}-\chi_{\mathrm{B}}\right)^2 \mathrm{eV}
$$
According to this equation, you have a stronger bond when the atomic orbital energy difference $$(\chi_A-\chi_B)$$ is high. Does this equation contradict the first quote?
This is unclear. How do you quantify how "similar" means?
I heard electronegative is tied to atomic radius is tied to atomic orbital energy.
What are two atoms that would in theory form an ionic compound if you use a naive theory but actually don't because the atomic orbitals are too dissimilar in energy levels according to molecular orbital theory?
>The essential point of Pauling electronegativity is that there is an underlying, quite accurate, semi-empirical formula for dissociation energies, namely:
>$$
E_{\mathrm{d}}(\mathrm{AB})=\frac{E_{\mathrm{d}}(\mathrm{AA})+E_{\mathrm{d}}(\mathrm{BB})}{2}+\left(\chi_{\mathrm{A}}-\chi_{\mathrm{B}}\right)^2 \mathrm{eV}
$$
According to this equation, you have a stronger bond when the atomic orbital energy difference $$(\chi_A-\chi_B)$$ is high. Does this equation contradict the first quote?