What is S = –2 hypernuclei and its nuclear emulation?

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In summary, S = –2 hypernuclei are exotic atomic nuclei containing one or more hyperons, which are baryons containing strange quarks. These hypernuclei provide insights into the strong nuclear force and the behavior of matter under extreme conditions. Nuclear emulation refers to using theoretical models and simulations to study the properties and interactions of S = –2 hypernuclei, helping researchers understand their structure, stability, and the role of strangeness in nuclear physics. This research has implications for understanding astrophysical phenomena, such as neutron stars and the early universe.
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kodama
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Experimental status of S = –2 hypernucle
i saw thisExperimental status of S = –2 hypernucle
Kazuma NAKAZAWA
Physics Department, Gifu University, Gifu 501-1193, Japan

link

https://journals.jps.jp/doi/pdf/10.7566/JPSCP.17.031001

and i would like to know more

its nuclear emulation

especially

page 3

Screenshot 2024-01-02 at 20-26-13 jpscp.17.031001.pdf.png


from page 3

https://journals.jps.jp/doi/pdf/10.7566/JPSCP.17.031001

what is V ? figure 3

by nuclear emulation V has mass 16-17 MeV and decay in to charged particles
 
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  • #2
kodama said:
View attachment 338041

from page 3

https://journals.jps.jp/doi/pdf/10.7566/JPSCP.17.031001

what is V ? figure 3

by nuclear emulation V has mass 16-17 MeV and decay in to charged particles
Not "V has mass". V has dimension of mass/energy.
Are you asking what is V or what is V0? These are different things (see equation (2)).
From my reading, V seems to be the actual binding energy of Ξ-. V0 is the total potential well depth - counting both the binding energy and zero point energy.
 
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  • #3
snorkack said:
Not "V has mass". V has dimension of mass/energy.
Are you asking what is V or what is V0? These are different things (see equation (2)).
From my reading, V seems to be the actual binding energy of Ξ-. V0 is the total potential well depth - counting both the binding energy and zero point energy.
but it decay in to 2 in to charged particles-(electron ?)
 
  • #4
kodama said:
by nuclear emulation V has mass 16-17 MeV and decay in to charged particles
V is a potential. It's not a particle and it doesn't decay to anything.
##\Xi^-## bound in nuclei decay to other things.
 
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  • #5
mfb said:
V is a potential. It's not a particle and it doesn't decay to anything.
##\Xi^-## bound in nuclei decay to other things.
is ##\Xi^-## a particle
 
  • #6
kodama said:
is ##\Xi^-## a particle
Yes, it is.
Decay to electron is allowed but low probability. For a lone Λ, decay to electron has a branching ratio of 0,083%
 
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  • #8
kodama said:
the reason I ask

https://www.linkedin.com/posts/robe...r-neutrinos-activity-7112652431959674880-687A
That I don´t think likely at all.
Late 1940s and 1950s were "particle zoo" period. Scientists had no clue what particles exist, they had not yet spotted the quark model periodicity system, so they had eyes open for any new particles they could see.
If there were any exotic particles, charged and low energy but with such a low formation cross-section that it was missed through 1950s, it is a weird coincidence that one should have been spotted back in 1946 and then none in 1950s.

On the other hand, 17 MeV quite fits the explanation in the article - potential well depth (baryon binding energy in nucleus+the zero point energy) and the binding energies of the stronger bound nuclei (like α) are in that region!
 
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  • #9
snorkack said:
That I don´t think likely at all.
LIf there were any exotic particles, charged and low energy
*uncharged but decay e+e-

snorkack said:
On the other hand, 17 MeV quite fits the explanation in the article - potential well depth (baryon binding energy in nucleus+the zero point energy) and the binding energies of the stronger bound nuclei (like α) are in that region!

not likely at all but it is possible 17 MeV could be a new unknown fundamental particle a boson?
 
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  • #10
kodama said:
but it is possible 17 MeV could be a new unknown fundamental particle a boson?

And what answer do you expect?
 
  • #11
weirdoguy said:
And what answer do you expect?
not likely at all could suggest a possible exploration

in Bayesian theory

if
arXiv:2311.18632 (hep-ex)
Observation of structures at ∼17 and ∼38 MeV/c2 in the γγ invariant mass spectra in pC, dC, and dCu collisions at plab of a few GeV/c per nucleon
Kh.U. Abraamyan, Ch. Austin, M.I. Baznat, K.K. Gudima, M.A. Kozhin, S.G. Reznikov, A.S. Sorin

is true

and
arXiv:2308.06473 (nucl-ex)
[Submitted on 12 Aug 2023]
Observation of the X17 anomaly in the decay of the Giant Dipole Resonance of 8Be
A.J. Krasznahorkay,
what could be the 17 MeV in
Experimental status of S = –2 hypernucle
Kazuma NAKAZAWA
Physics Department, Gifu University, Gifu 501-1193, Japan

multiple experiment with 17 MeV decay in to e+e-
 
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FAQ: What is S = –2 hypernuclei and its nuclear emulation?

What is a S = –2 hypernucleus?

A S = –2 hypernucleus is a type of atomic nucleus that contains hyperons with a strangeness quantum number (S) of –2. These hyperons are typically Ξ (Xi) particles, which are baryons containing two strange quarks. The presence of these strange quarks gives the hypernucleus unique properties compared to ordinary nuclei composed of protons and neutrons.

How are S = –2 hypernuclei produced?

S = –2 hypernuclei are generally produced in high-energy particle collisions, such as those occurring in particle accelerators. These collisions can create Ξ hyperons, which can then be captured by a nucleus to form a hypernucleus. Specialized experiments and detectors are used to identify and study these rare and short-lived nuclei.

What is the significance of studying S = –2 hypernuclei?

Studying S = –2 hypernuclei provides valuable insights into the strong interaction, which is the fundamental force that binds quarks together in hadrons and holds atomic nuclei together. Investigating these hypernuclei helps scientists understand how the presence of strange quarks affects nuclear structure and interactions, contributing to our broader knowledge of quantum chromodynamics (QCD) and the behavior of matter under extreme conditions.

What are the challenges in creating and detecting S = –2 hypernuclei?

Creating and detecting S = –2 hypernuclei is challenging due to their rarity and short lifetimes. High-energy collisions required to produce Ξ hyperons occur infrequently, and the resulting hypernuclei often decay rapidly into other particles. Advanced particle detectors, precise timing measurements, and sophisticated data analysis techniques are necessary to identify and study these elusive nuclei accurately.

What is nuclear emulation in the context of S = –2 hypernuclei?

Nuclear emulation in the context of S = –2 hypernuclei refers to the use of theoretical models and computer simulations to replicate and study the properties and behaviors of these exotic nuclei. Emulation allows scientists to predict various characteristics of hypernuclei, such as their binding energies, decay modes, and interaction strengths, providing a deeper understanding of their nature and guiding experimental efforts.

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