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Solution A, while in a 1.0 cm cell, has an absorbance of 0.390 and a [Cu2+] = 0.0283 M. Then, 6.57 mL of solution A is diluted with pure water to 100.0 mL. What is the absorbance of this diluted solution?
The below is what I did. But I am not sure about the answer. Can you please check it? If there is something wrong, please correct! Thanks a lot!
concentration of dilute solution----6.57ml of 0.0283M = 100.0ml x M
Solve for M----( 100 x 0.0283 ) / 6.57 = 0.4307
Solve for absorbance: 0.390/A = 0.0283/0.4307
==> Absorbance (A) = 5.93607
The below is what I did. But I am not sure about the answer. Can you please check it? If there is something wrong, please correct! Thanks a lot!
concentration of dilute solution----6.57ml of 0.0283M = 100.0ml x M
Solve for M----( 100 x 0.0283 ) / 6.57 = 0.4307
Solve for absorbance: 0.390/A = 0.0283/0.4307
==> Absorbance (A) = 5.93607