- #1
lemon
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Q1. A cyclist can develop power of 400W and a top speed on a level road of 7.5m/s. The drag force against which the cyclist is working is?
Q2. A constant force drags a block of mass 2kg up a smooth slope at a constant speed of 1m/s, exerting power or 10W. The angle of the slope is?
2. P=F x V
mgsin(theta)
F=ma
3Q1. 400W/7.5m/s = 53.3N (3s.f.)
This is just a simple solution stating that the drag force is equal to the forward thrust force, right? As not mention of Frictional Force has been mentioned.
3Q2. If there is a constant force there is no acceleration.
Force acting up the slope - P/V = 10/1 = 10N
Force acting downwards - mgsin(theta). Now I'm stuck. I think I need to calculate F-F1=mgsin(theta). But I have two missing numbers for this equation. If I try to find acceleration using F=ma I get 10N/2kg = 5ms-2. But if this is a constant force this is no acceleration.
Confused. Please help?
Q2. A constant force drags a block of mass 2kg up a smooth slope at a constant speed of 1m/s, exerting power or 10W. The angle of the slope is?
2. P=F x V
mgsin(theta)
F=ma
3Q1. 400W/7.5m/s = 53.3N (3s.f.)
This is just a simple solution stating that the drag force is equal to the forward thrust force, right? As not mention of Frictional Force has been mentioned.
3Q2. If there is a constant force there is no acceleration.
Force acting up the slope - P/V = 10/1 = 10N
Force acting downwards - mgsin(theta). Now I'm stuck. I think I need to calculate F-F1=mgsin(theta). But I have two missing numbers for this equation. If I try to find acceleration using F=ma I get 10N/2kg = 5ms-2. But if this is a constant force this is no acceleration.
Confused. Please help?