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k0k
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A 1250-kg race car accelerates uniformly from rest to 30.0m/s in 4.00s on a horizontal surface with no friction. What must be the average power output of its motor? (Ans:141kW)
--
P=E/t
F=ma
Ek=1/2mv^2
--
P=E/t
P=Ek/t
=(.5X1250kgX15.0m/s^2) / (4.00s)
=35156.25 W
How exactly do I start this off? I assume that the change in energy should be kinetic only, right?.
--
P=E/t
F=ma
Ek=1/2mv^2
--
P=E/t
P=Ek/t
=(.5X1250kgX15.0m/s^2) / (4.00s)
=35156.25 W
How exactly do I start this off? I assume that the change in energy should be kinetic only, right?.