- #1
davidwinth
- 101
- 8
I am trying to find the chemical formula for moist air. By using an online psychrometric calculator, I find that moist air at 20°C has a mol fraction of water=0.0235 and mol fraction dry air=0.9765.
Does this mean like this?
0.9765(O2 + 3.76N2) + 0.0235H2O ----> 41.55(O2 + 3.76N2) + H20
My confusion comes when I think about 1 mol of air. Does 1 mol of air have 1 mol of oxygen and 3.76 mols of N2 or does 1 mol of air contain .21 mols of oxygen and .79 mols of N2? If the latter, then I think the formula above is wrong and it should be:
0.9765(0.21O2 + 0.79N2) + 0.0235H2O
----> 0.205O2 + 0.771N2 + 0.0235H2O
----> O2+ 3.76N2 + 0.115H2O.
Which one is right, or is neither one right?
Thanks!
Does this mean like this?
0.9765(O2 + 3.76N2) + 0.0235H2O ----> 41.55(O2 + 3.76N2) + H20
My confusion comes when I think about 1 mol of air. Does 1 mol of air have 1 mol of oxygen and 3.76 mols of N2 or does 1 mol of air contain .21 mols of oxygen and .79 mols of N2? If the latter, then I think the formula above is wrong and it should be:
0.9765(0.21O2 + 0.79N2) + 0.0235H2O
----> 0.205O2 + 0.771N2 + 0.0235H2O
----> O2+ 3.76N2 + 0.115H2O.
Which one is right, or is neither one right?
Thanks!
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