What Is the Coefficient of Kinetic Friction in This Physics Problem?

[Spartan Erik]

Homework Statement

"A forward horizontal force of 50N is used to pull a crate, which weighs 250N, at a constant velocity across a horizontal floor. The coefficient of kinetic friction is:"

Homework Equations

Frictional force = coefficient of kinetic friction x normal force

The Attempt at a Solution

This problem seems too easy, that's why I'm wondering if I might be wrong:

Frictional force = coefficient of kinetic friction x normal force
50N = coefficient x 250N
50N / 250N = coefficient
coefficient = 0.2

Is that all? Thanks

 

[Perillux]

yup that is correct.

 

[baba89]

for your help.

I can confirm that your solution is correct. However, I would like to add that the coefficient of kinetic friction is a constant value that depends on the two surfaces in contact. It is a measure of the roughness of the surfaces and determines the amount of resistance to motion. In this case, the coefficient of kinetic friction between the crate and the floor is 0.2. To ensure that the crate continues to move at a constant velocity, the applied force of 50N must be equal to the frictional force of 50N, as per Newton's first law of motion.