What is the Coefficient of Static Friction for Two Tied Objects?

In summary: So is it the same value as when the 5kg block was on top? (Actually, it's not, but close.)What other way can I solve the tension in the string without equating the 2 equations? I still got the correct answer using this method by the way.You can use Newton's 2nd law to find the acceleration of the objects, and then use that acceleration to find the tension in the string. It's just that the solution will be a bit less direct and, since the equation for friction force depends on acceleration, the solution will include a (small) error. (If you were to do this problem numerically, you would find that the "static" friction force starts
  • #1
oMovements
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Homework Statement


Two objects are made of identical material and are tied together with string. The first object has a mass of 5.0kg and the second object has a mass of 3.0kg. Students measure the maximum force of static friction as 31.4N to move both objects across a horizontal surface.
a) What is the coefficient of static friction?
b) What is the magnitude of the tension in the string if they pull on the first object?
c) A student pushes the 3.0kg object with a force of 15.0[down]. What are the magnitudes of the maximum force of static friction and the tension now?
d) Will your answers to (c) change if the student pushes down on the 5.0kg object instead? Explain.

Homework Equations



The Attempt at a Solution


a) μs=Fs / Fn
=31.4 / (8)(9.8)
μs= 0.40

b) To solve B) I came up with two equations, one for each object and equated them to solve for acceleration, and tension.

Fs-Ft=ma
31.4-Ft=5a
Ft=31.4-5a
Ft= 11.78N <-- I found this by finding the acceleration first, and subbing it into 31.4-5a

Ft=ma
31.4-5a=3a
31.4=8a
a=2.925m/s2

c)

d)

I know how to solve a) b) but I have no clue how to solve c). How would I go about doing it?
 
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  • #2
oMovements said:
b) To solve B) I came up with two equations, one for each object and equated them to solve for acceleration, and tension.
What acceleration? This is still the static case.

For c, what is the normal force from the surface on the 3kg block now? (Is the 15 in Newtons or kg-weight?)
 
  • #3
oMovements said:
b) To solve B) I came up with two equations, one for each object and equated them to solve for acceleration, and tension.

Fs-Ft=ma
31.4-Ft=5a
Ft=31.4-5a
Ft= 11.78N <-- I found this by finding the acceleration first, and subbing it into
It is probably best not to do it that roundabout way, because you are assuming that coefficient of kinetic friction is going to be equal to the coefficient of static friction and you know, in principle, this is almost never true.

All you need to consider is that the 3kg object (with μs=0.4) is being dragged by the string. Find the max tension in the string.

I know how to solve a) b) but I have no clue how to solve c). How would I go about doing it?
In part (c), someone is pushing down on the object, increasing the normal force between the object and the surface it sits on. You need to now find the increased tangential friction force.
 
  • #4
haruspex said:
What acceleration? This is still the static case.

For c, what is the normal force from the surface on the 3kg block now? (Is the 15 in Newtons or kg-weight?)

15N. There is an acceleration because the it states "Students measure the maximum force of static friction as 21.4N to move both objects across a horizontal surface." and static friction can also cause an object to move if I remember correctly.
 
  • #5
NascentOxygen said:
It is probably best not to do it that roundabout way, because you are assuming that coefficient of kinetic friction is going to be equal to the coefficient of static friction and you know, in principle, this is almost never true.

All you need to consider is that the 3kg object (with μs=0.4) is being dragged by the string. Find the max tension in the string.In part (c), someone is pushing down on the object, increasing the normal force between the object and the surface it sits on. You need to now find the increased tangential friction force.

What other way can I solve the tension in the string without equating the 2 equations? I still got the correct answer using this method by the way.

I'm also still confused how to solve c)
 
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  • #6
With what force is the 3kg block in (c) pushing down onto the table?
 
  • #7
NascentOxygen said:
With what force is the 3kg block in (c) pushing down onto the table?

Force of 15N
 
  • #8
oMovements said:
Force of 15N
What force was the 3kg block exerting on the table before the student pressed down on it? What do you think that force will increase by when the student presses down?
There is an acceleration because the it states "Students measure the maximum force of static friction as 21.4N to move both objects across a horizontal surface."
That's the force required to overcome static friction. Until it is overcome there is no acceleration.
and static friction can also cause an object to move if I remember correctly.
Yes, but it cannot cause the object to move relative to the surface. Friction always opposes relative motion of the surfaces in contact.
 
  • #9
oMovements said:
Force of 15N
Plus its weight!
 

FAQ: What is the Coefficient of Static Friction for Two Tied Objects?

What is static friction?

Static friction is the force that acts between two surfaces that are in contact with each other, when there is no relative motion between the two surfaces. It is a type of friction that prevents an object from moving when a force is applied to it.

What is the "Static Friction String Problem"?

The "Static Friction String Problem" is a physics problem that involves a block of mass attached to a string, which is pulled with a certain force. The question is to determine the maximum tension that the string can withstand before the block starts to move.

How is the maximum tension calculated in the "Static Friction String Problem"?

The maximum tension in the string can be calculated by using the equation T = μsN, where T is the maximum tension, μs is the coefficient of static friction between the block and the surface it is resting on, and N is the normal force exerted on the block by the surface.

What factors affect the maximum tension in the "Static Friction String Problem"?

The maximum tension in the string is affected by the coefficient of static friction, the weight of the block, and the angle at which the string is pulled. A higher coefficient of static friction and a larger weight will result in a higher maximum tension, while a smaller angle will decrease the maximum tension.

What is the real-life significance of the "Static Friction String Problem"?

The "Static Friction String Problem" is a simplified version of real-life situations where friction plays a crucial role. It can help us understand the concept of static friction and how it affects the movement of objects in our daily lives. It is also used in engineering and design to determine the strength of materials and structures.

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