- #1
porschedriver192
- 12
- 0
Please Help! - Specific Heat Problem...
I have been stuck for a while, it's online (Webassign), so it told me my answer was wrong.
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A 6.3x10^2 g sample of water at 90.0°C is mixed with 4.45x10^2 g of water at 22.0°C. Assume no heat loss to the surroundings. What is the final temperature of the mixture?
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The formula I know is right:
(cp)(m)(Tf- Ti) = (cp)(m)(Tf- Ti)
cp= spec. heat
m = mass
Tf = final Temp
Ti = initial Temp
--------
work:
converted grams into kilograms...
cp water, given
||
(4186) (.630) (x-90) = (4186) (.445) (x-22)
774.41x = 196365.26
x = <<<it says it's wrong>>>
Where did I slip up?
Thanks.
I have been stuck for a while, it's online (Webassign), so it told me my answer was wrong.
-------
A 6.3x10^2 g sample of water at 90.0°C is mixed with 4.45x10^2 g of water at 22.0°C. Assume no heat loss to the surroundings. What is the final temperature of the mixture?
-------
The formula I know is right:
(cp)(m)(Tf- Ti) = (cp)(m)(Tf- Ti)
cp= spec. heat
m = mass
Tf = final Temp
Ti = initial Temp
--------
work:
converted grams into kilograms...
cp water, given
||
(4186) (.630) (x-90) = (4186) (.445) (x-22)
774.41x = 196365.26
x = <<<it says it's wrong>>>
Where did I slip up?
Thanks.