- #1
superslow991
- 78
- 1
Homework Statement
An ac series circuit consists of a voltage source of frequency f = 60 Hz and voltage amplitude V, a resistor of resistance R = 163 ohms and a capacitor of capacitance C = 6.2x10^-6 F. What must the source voltage amplitude V be for the average electrical power consumed in the resistor to be 529 watts? There is no inductance in the circuit.
Homework Equations
XC = 1 / (2 × π × f × C)
Z = √(R2 + X2)
P=V^2/R
The Attempt at a Solution
So first i calculated the reactance and got 1/(2*π*60*6.2*10^-6)= 428.05
next impedance-√(163^2 + 428.05^2)= 458.0
last i used the power equation - 529=v^2/458.0 and solved for v and got 492.2 V
My only question is I've checked different answers online and saw some as V = 1165 or 1166
just wondering if i did the math right on this question. Any help is appreciated.