- #1
Quelsita
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QUESTION:
Suppose the numerical value of 492 is assigned to the ice point temperature [tex]\theta[/tex]ice=492.
a) Find the steam point temperature on this scale.
b) Calculate the temperature interval between the steam point and the ice point on
this scale.
SOLUTION a :
We know that the ratio [tex]\theta[/tex]ice/[tex]\theta[/tex]steam = 1.3661
and that [tex]\theta[/tex]steam - [tex]\theta[/tex]ice = 100
thus,
[tex]\theta[/tex]steam = (1.3661)([tex]\theta[/tex]ice)
[tex]\theta[/tex]steam = (1.3661) (492)
[tex]\theta[/tex]steam = 671.12
SOLUTION b:
If [tex]\theta[/tex]ice=492 and
[tex]\theta[/tex]steam=672.12
then
[tex]\theta[/tex]steam -[tex]\theta[/tex]ice =180.12
Is this really correct?
Thanks!
Suppose the numerical value of 492 is assigned to the ice point temperature [tex]\theta[/tex]ice=492.
a) Find the steam point temperature on this scale.
b) Calculate the temperature interval between the steam point and the ice point on
this scale.
SOLUTION a :
We know that the ratio [tex]\theta[/tex]ice/[tex]\theta[/tex]steam = 1.3661
and that [tex]\theta[/tex]steam - [tex]\theta[/tex]ice = 100
thus,
[tex]\theta[/tex]steam = (1.3661)([tex]\theta[/tex]ice)
[tex]\theta[/tex]steam = (1.3661) (492)
[tex]\theta[/tex]steam = 671.12
SOLUTION b:
If [tex]\theta[/tex]ice=492 and
[tex]\theta[/tex]steam=672.12
then
[tex]\theta[/tex]steam -[tex]\theta[/tex]ice =180.12
Is this really correct?
Thanks!