MHB What is the Cost of One Jump Ring in a $8 Pack of 1000?

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The cost of each jump ring in an $8 pack of 1,000 is calculated by dividing $8 by 1,000, resulting in 0.008 dollars per ring. This value translates to 0.8 cents per jump ring, which can also be expressed as "one tenth of 8 cents." Another perspective is that it equates to 4 cents for every 5 jump rings. The confusion primarily lies in interpreting 0.008 as either dollars or cents, but it is confirmed to be in dollars. Understanding this calculation clarifies the cost per jump ring effectively.
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If I get a pack of 1,000 jump rings (for jewelry), and the bag costs me $8, how much is EACH jump ring? is it 8 divided by 1,000, which is .008 cents per ring, or is this .008 dollars, and I move the decimal spaces two to the left to get cents? I m a bit confused... Thanks!
 
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I would write:

$$\frac{\$8}{1000 \text{ jump rings}}\cdot\frac{100\text{ cents}}{\$1}=\frac{4}{5}\,\frac{\text{cents}}{\text{jump ring}}$$
 
MarkFL said:
I would write:

$$\frac{\$8}{1000 \text{ jump rings}}\cdot\frac{100\text{ cents}}{\$1}=\frac{4}{5}\,\frac{\text{cents}}{\text{jump ring}}$$

Thank you very much! So the .008 was just .008 "dollars" earlier? $8/1000 = 0.008 Dollars?

Is that the same as saying "one tenth of 8 cents per ring" ?
 
Enoonmai said:
Thank you very much! So the .008 was just .008 "dollars" earlier? $8/1000 = 0.008 Dollars?

Is that the same as saying "one tenth of 8 cents per ring" ?

Yes, and another way to look at it is "4 cents for every 5 jump rings."
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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