What is the covariance matrix (X,Y) for the joint distribution of X and Y?

In summary, we have two random variables X and Y representing the number of clubs and queens, respectively, in a 13 card hand drawn at random without replacement from a 52 card deck. The pdf of X is given by f_x(x) = (13 choose x)(39 choose 13-x) / (52 choose 13) for x = 0 to 13 and 0 otherwise. The joint distribution of X and Y is (13 choose x)(5 choose y)(34 choose 13-x-y)/ (52 choose 13) for 0 =< x =< 13, 0 =< y =< 4, 0 <= x+y <= 13, and 0 otherwise. The expected
  • #1
nikki92
40
0
X = # of clubs in a 13 card hand drawn at random without replacement from 52 card deck
Y= # of queens in the same 13 card hand

the pdf of x is f_x (x) = (13 choose x)( 39 choose 13-x) / (52 choose 13) for x=< x =< 13
and o otherwise

the joint distribution of x and y = (13 choose x) ( 5 choose y) ( 34 choose 13-x-y)/ (52 choose 13) for 0 =<x =<13 0 =< y =< 4 0<=x+y<=13 and 0 otherwise

What is E(Y) and what is the covariance matrix (X,Y)?

E[Y] = Sum y=1 to 4 of y* (4 choose y)(48 choose 13-y)/ (52 choose 13) ?

I have no idea on the matrix.
 
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  • #2
Hey nikki92.

The covariance of two random variables is given by Cov(X,Y) = E[XY] - E[X]E[Y] where E[XY] = Summation (over x) Summation over y P(X=x,Y=y)*xy (Or an integral for continuous random variable).

The covariance matrix has Cov(Xi,Xj) at the (i,j) position in the matrix and note that Cov(Xi,Xi) = E[Xi^2] - {E[Xi]}^2 = Var[Xi] so you will have four entries with Var[X1], Var[X2] in (1,1) (2,2) and Cov(X,Y) in the other positions.
 

FAQ: What is the covariance matrix (X,Y) for the joint distribution of X and Y?

How many different combinations of card hands are possible?

The total number of possible combinations of card hands is 2,598,960. This number is calculated by taking the total number of cards in a deck (52) and using the formula nCr = n!/(r!(n-r)!), where n is the total number of cards and r is the number of cards in a hand.

What are the chances of getting a royal flush in a five-card hand?

The probability of obtaining a royal flush (10, J, Q, K, A of the same suit) in a five-card hand is 0.000154%. This means that in a random deal of five cards, you have a 1 in 649,740 chance of getting a royal flush.

Can the distribution of card hands be affected by shuffling techniques?

Yes, the distribution of card hands can be affected by shuffling techniques. A thorough and randomized shuffling technique, such as the riffle shuffle, can greatly increase the randomness of card distribution and decrease the predictability of certain hands.

How many different 5-card poker hands are possible?

There are 2,598,960 possible 5-card poker hands. This includes all possible combinations of hands, from the highest ranking royal flush to the lowest ranking high card hand.

Is it possible to calculate the exact odds of receiving a specific hand in a game of poker?

Yes, it is possible to calculate the exact odds of receiving a specific hand in a game of poker. However, the calculation becomes increasingly complex as the number of cards in the hand increases. For example, the odds of getting a specific 7-card hand in Texas Hold'em can only be estimated through computer simulations.

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