- #1
Bigworldjust
- 54
- 0
Homework Statement
The electric field in a 1.2mm x 1.2mm square aluminum wire is 2.0×10^-2 V/m What is the current in the wire? I = ?A
Homework Equations
E = V/length
R = ρL / A
I = V/R = V*A/ ρ*L
The Attempt at a Solution
Electrical field strength E = V / length = 2 x 10^-2 V/m
Resistance of wire R = ρL / A; ρ for aluminium = 2.65 x 10^-8 ohm-m
A = 1.2*1.2 = 1.44 mm^2 = 1.44 x 10^-6 m^2
Current I = V / R = V*A / ρ*L = (V/L)*(A/ ρ) = 2 x 10^-2 (1.44 x 10^-6 / 2.65 x 10^-8 ) = 1.087 A
Alright that was my final answer, but I am just asking here to double check if it is right or not because I only have one more try on this question, and I don't want to get it wrong, lol. Did I make any mistakes? Thank you!