- #1
Bipolarity
- 776
- 2
The pressure of a liquid of constant density at depth 'h' is given by the equation:
[tex] P = hρg [/tex]
I am trying to understand the derivation of this equation. I understand it perfectly for liquid columns with rectangular liquid columns but I can't see why it works if the shape of the fluid column is irregular.
[tex] P = \frac{F}{A} = \frac{mg}{\frac{V}{h}} = hρg [/tex]
The problem is that [itex] \frac{V}{h} = A [/itex] only if it is rectangular shaped, right?
So why should we allowed to generalize it for all fluid columns?
BiP
[tex] P = hρg [/tex]
I am trying to understand the derivation of this equation. I understand it perfectly for liquid columns with rectangular liquid columns but I can't see why it works if the shape of the fluid column is irregular.
[tex] P = \frac{F}{A} = \frac{mg}{\frac{V}{h}} = hρg [/tex]
The problem is that [itex] \frac{V}{h} = A [/itex] only if it is rectangular shaped, right?
So why should we allowed to generalize it for all fluid columns?
BiP