What is the Derivative of sin x^5?

In summary, the question is asking to find the derivative of the integral of sin t with respect to t with limits of integration from 0 to x^5. The answer is 5x^4 sin (x^5). The Leibnitz rule can be used to differentiate an integral with variable upper limit.
  • #1
char808
27
0
Find the derivative.

d/dx [tex]\int[/tex][tex]\stackrel{x^5}{o}[/tex] sint dt

I came up with sin x^5.

The answer is 5x^4 sin (x^5).



Not sure what I'm missing here.
 
Last edited:
Physics news on Phys.org
  • #2
Is the question:

Integrate x^5*sin(t) with respect to 't', then differentiate the result with respect to 'x'?
 
  • #3
x^5 and 0 are the limits, right?

First: you integrate sint with respect to t.
Second: Apply the limits to the value you obtained for the integer. You'll get two terms, get it?

Then, derive this result with respect to x.
 
  • #4
emol1414 said:
x^5 and 0 are the limits, right?

First: you integrate sint with respect to t.
Second: Apply the limits to the value you obtained for the integer. You'll get two terms, get it?

Then, derive this result with respect to x.

That works in this problem but the point is likely to use Leibnitz rule for differentiating an integral with variable upper limit. It would work even if you had something more difficult than sin(t) that you couldn't find the antiderivative for. The basic Leibnitz rule is:

[tex]\frac d {dx}\int_a^{g(x)} f(t)\, dt = f(g(x))\cdot g'(x)[/tex]
 
  • #5
The repaired LaTeX is below.
char808 said:
Find the derivative.

d/dx [tex]\int[/tex][tex]\stackrel{x^5}{o}[/tex] sint dt

I came up with sin x^5.

The answer is 5x^4 sin (x^5).



Not sure what I'm missing here.

[tex]d/dx \int_0^{x^5} sint dt[/tex]
To the OP: click the integral to see the LaTeX code I used.
The integral in the original post was confusing to at least one person who didn't understand that x5 was one of the limits of integration.

Also, don't use o (the letter) where 0 (the numeral) is intended.

BTW, there is no such word as "intergral" - the word is integral.
 

FAQ: What is the Derivative of sin x^5?

What is the basic concept of finding the derivative of sin x^5?

The derivative of sin x^5 is the rate of change of the function at any given point. It tells us how quickly the function is changing at that point.

What is the formula for finding the derivative of sin x^5?

The formula for finding the derivative of sin x^5 is 5x^4cos(x^5).

How do you solve for the derivative of sin x^5?

To solve for the derivative of sin x^5, we use the power rule and the chain rule. First, we bring down the power of 5 and multiply it by the coefficient 5 to get 5x^4. Then, we take the derivative of the inner function, which is x^5, to get 5x^4. Finally, we multiply these two values together to get the final result of 5x^4cos(x^5).

Why is it important to find the derivative of sin x^5?

It is important to find the derivative of sin x^5 because it allows us to analyze the behavior of the function at any given point. It also helps us to find the slope of the tangent line, which is useful in many applications such as optimization problems and curve sketching.

What are some other examples of functions that follow a similar process for finding the derivative as sin x^5?

Other examples of functions that follow a similar process for finding the derivative as sin x^5 include cos x^5, tan x^5, and any other trigonometric function raised to a power.

Back
Top