What is the derivative of (sin x)^sin x?

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In summary, the conversation discusses solving the function f(x) = (sin x)^(sin x) by taking the logarithm of both sides, simplifying the expression, and differentiating both sides. The other person also suggests using a property of the natural log function to rewrite the equation before differentiating.
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lucphysics
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Homework Statement


f(x)= (sin x)^(sin x)

Homework Equations

The Attempt at a Solution


Taking logarithm on both sides I get:
ln y = ln ((sin x)^(sin x))
 
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  • #2
Yes...you are on the right track, why stop there? Simplify the expression and differentiate both sides.
 
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lucphysics said:

Homework Statement


f(x)= (sin x)^(sin x)

Homework Equations

The Attempt at a Solution


Taking logarithm on both sides I get:
ln y = ln ((sin x)^(sin x))
That's a good start. Can you rewrite the right side by using a property of the natural log function?
After that, you can differentiate both sides of the resulting equation.
 
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  • #4
Thank you!
 

FAQ: What is the derivative of (sin x)^sin x?

What is the derivative of (sin x)^sin x?

The derivative of (sin x)^sin x is cos x * (sin x)^sin x * (ln(sin x) + cos x * ln(sin x)). This can also be written as (sin x)^sin x * (cos x * ln(sin x) + ln(cos x))

How do you find the derivative of (sin x)^sin x?

To find the derivative of (sin x)^sin x, you can use the chain rule. First, rewrite the function as e^(sin x * ln(sin x)). Then, take the derivative of the exponent, sin x * ln(sin x), using the product rule and the derivative of sin x. Finally, multiply the derivative of the exponent by the original function, e^(sin x * ln(sin x)).

Is there a simpler way to express the derivative of (sin x)^sin x?

Yes, you can use the power rule to simplify the derivative of (sin x)^sin x to cos x * (sin x)^sin x * (1 + ln(sin x)).

Can you explain the steps to find the derivative of (sin x)^sin x in more detail?

First, rewrite the function as e^(sin x * ln(sin x)). Then, take the derivative of the exponent using the product rule: (ln(sin x) + cos x * ln(sin x)). Next, use the chain rule to find the derivative of sin x, which is cos x. Finally, multiply the derivative of the exponent by the original function, e^(sin x * ln(sin x)).

Are there any other methods to find the derivative of (sin x)^sin x?

Yes, you can also use logarithmic differentiation to find the derivative of (sin x)^sin x. This involves taking the natural log of both sides of the original function, then using properties of logarithms to simplify the expression. Finally, take the derivative of both sides and solve for the derivative of (sin x)^sin x.

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