- #1
Ramazan Duzgun
- 11
- 0
- TL;DR Summary
- Either natural or forced air cooled convection can be thought, I have a 400 A (Vforward=1.55 V) power diode and I need to design a heatsink for that.
In reference of Ned Mohan's book, I have designed a heatsink, firstly natural convection taken into account, but laboratory test results and theoretical calculations are not matching.
The test results:
For 40 A (means 62 W), 30 Celsius ambient temp, it raised up 51 Celsius. So, Rs-a = (51-30)/62 = 0.338 Celsius/Watt.
For 60A (means 93 W), it raised up 64 Celsius. Then, Rs-a = (64-30)/93 = 0.365 Celsius/Watt.
In theoretical calculations, for instance, for 40A, it supposed be Rs-a = 1.43 Celsius/Watt. This is not feasible.
I have also tried the other author's calculation methods, like B. W. Williams, but it was also not feasible.
However, there must be exact solution for heatsink calculation. What is the design methodology of a heatsink ?
Thanks!
The test results:
For 40 A (means 62 W), 30 Celsius ambient temp, it raised up 51 Celsius. So, Rs-a = (51-30)/62 = 0.338 Celsius/Watt.
For 60A (means 93 W), it raised up 64 Celsius. Then, Rs-a = (64-30)/93 = 0.365 Celsius/Watt.
In theoretical calculations, for instance, for 40A, it supposed be Rs-a = 1.43 Celsius/Watt. This is not feasible.
I have also tried the other author's calculation methods, like B. W. Williams, but it was also not feasible.
However, there must be exact solution for heatsink calculation. What is the design methodology of a heatsink ?
Thanks!