- #1
Ry122
- 565
- 2
for the matrix
{5,0}
{2,-2}
when determining the eigenvector for its 2nd eigenvalue, -2, you would start out by doing
{5--2 ,0}
{2 ,-2--2}
giving
{7,0}
{2,0}
In equation form this is
7u + 0v = 0
2u + 0v = 0
Ordinarily I would set u or v to a value and solve for the other letter.
But in this case this can't be done since in both equations v has a coefficient of 0.
So what would you do in this situation?
{5,0}
{2,-2}
when determining the eigenvector for its 2nd eigenvalue, -2, you would start out by doing
{5--2 ,0}
{2 ,-2--2}
giving
{7,0}
{2,0}
In equation form this is
7u + 0v = 0
2u + 0v = 0
Ordinarily I would set u or v to a value and solve for the other letter.
But in this case this can't be done since in both equations v has a coefficient of 0.
So what would you do in this situation?