What is the electric field at the point x = 3.5 m, y = 2.0 m?

In summary: The electric field at a given point is equal to the negative gradient of the electric potential at that point. In summary, the electric field at (3.5, 2.0) is (5.95, 5.95) V/m and the initial acceleration of a particle released from this point is 3.56 x 10^11 m/s^2.
  • #1
Bri15
2
0
1. Homework Statement [/b]

The electric potential in a region of space is given by V = axy where a = 1.7 V/m2.

(a) What is the electric field at the point x = 3.5 m, y = 2.0 m? Give your answer in unit
vector notation.

(b) If a particle of mass m = 1.67 × 10 −27 kg and charge q = +1.6 × 10 −19 C is released from
this point, what is the magnitude of its initial acceleration?

Homework Equations



V=axy

The Attempt at a Solution


(a)V=(1.7)(3.5)(2)
11.9
This seems to simple is this correct. Also do not understand unit vector notation.
(b) unsure of the equation to use
 
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  • #2
Bri15 said:
1. Homework Statement [/b]

The electric potential in a region of space is given by V = axy where a = 1.7 V/m2.

(a) What is the electric field at the point x = 3.5 m, y = 2.0 m? Give your answer in unit
vector notation.

(b) If a particle of mass m = 1.67 × 10 −27 kg and charge q = +1.6 × 10 −19 C is released from
this point, what is the magnitude of its initial acceleration?

Homework Equations



V=axy

The Attempt at a Solution


(a)V=(1.7)(3.5)(2)
11.9
This seems to simple is this correct. Also do not understand unit vector notation.
(b) unsure of the equation to use

(a) What's the formula for the electric field, given the potential?
(b) F = ma
 
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Likes guofei yan

Related to What is the electric field at the point x = 3.5 m, y = 2.0 m?

1. What is the definition of an electric field?

The electric field is a physical quantity that describes the force experienced by a charged particle at a specific point in space. It is a vector quantity, meaning it has both magnitude and direction.

2. How is the electric field calculated at a specific point?

The electric field at a point is calculated by dividing the force exerted on a test charge by the charge itself. This can also be expressed as the product of the charge and the electric field strength.

3. What is the unit of measurement for electric field?

The unit of measurement for electric field is Newtons per coulomb (N/C) in the SI system. In the CGS system, it is measured in dynes per statcoulomb (dyn/statC).

4. How is the direction of the electric field determined?

The direction of the electric field is determined by the direction of the force that would be experienced by a positive test charge placed at that point. If the field lines are pointing away from the point, the electric field is directed outward, and if they are pointing towards the point, the field is directed inward.

5. How does the distance from a charged object affect the electric field at a point?

The electric field at a point is inversely proportional to the square of the distance from a charged object. This means that as the distance increases, the electric field decreases. In other words, the farther away you are from a charged object, the weaker its electric field will be at your location.

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